HackerRank Write a function solution in python YASH PAL, 31 July 202430 October 2025 In this HackerRank write a function problem solution in python An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.In the Gregorian calendar, three conditions are used to identify leap years: The year can be evenly divided by 4, is a leap year, unless:The year can be evenly divided by 100, it is NOT a leap year, unless:The year is also evenly divisible by 400. Then it is a leap year.This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years.TaskGiven a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False. Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.HackerRank Write a Function solution in Python 2.def is_leap(year): leap = False # Write your logic here if (year % 100 == 0) and (year %400 != 0): leap = False elif (year % 4 == 0): leap = True return leap Problem solution in Python 3.def is_leap(year): leap = False if year%4 == 0: if year%100 == 0: if year%400 == 0: leap = True else: leap = False else: leap = True else: leap = False return leapProblem solution in pypy programming.def is_leap(year): if year%4!=0: return False if year%100==0: if year%400==0: return True return False return FalseProblem solution in pypy3 programming.def is_leap(year): leap = False if year%4: return False elif year%100: return True elif year%400: return False else: return True coding problems solutions Hackerrank Problems Solutions Python Solutions HackerRank