Hackerrank String Formatting solution in Python

In this HackerRank String Formatting problem solution in Python Given an integer, n, print the following values for each integer i from 1 to n:

• Decimal
• Octal
• Hexadecimal (capitalized)
• Binary

HackerRank String formatting solution in Python 2 programming.

N = int(raw_input())

width = len(str(bin(N)))-2

for num in range(1,N+1):
    for base in 'doXb':
        print '{0:{width}{base}}'.format(num, base=base, width=width),
    print

Problem solution in Python 3 programming.

N = int(input())
l = len(bin(N)) - 2

for i in range(1, N + 1):
    f = ""
    for c in "doXb":
        if f:
            f += " "
        f += "{:>" + str(l) + c + "}"
    print(f.format(i, i, i, i))

Problem solution in PyPy programming.

n = int(raw_input())
width = len("{0:b}".format(n))
for i in xrange(1,n+1):
    print "{0:{width}d} {0:{width}o} {0:{width}X} {0:{width}b}".format(i, width=width)

Problem solution in pypy3 programming.

def print_formatted(number):
    width=len(bin(number))-2
    for num in range(1,number+1): 
        for base in ('d', 'o', 'X', 'b'):
            print("{0:{width}{base}}".format(num, base=base, width=width), end=' ')
        print()

Note: in the above code in the for loop there is only one single line of code. for visibility purpose am going to cut down that line of code into another line.