HackerRank Words Score problem solution in Python

HackerRank Words Score problem solution in Python – In this Words Score challenge, the task is to debug the existing code to successfully execute all provided test files.

In this challenge, the task is to debug the existing code to successfully execute all provided test files.

Consider that vowels in the alphabet are a, e, i, o, u and y.

Function score_words takes a list of lowercase words as an argument and returns a score as follows:

The score of a single word is 2 if the word contains an even number of vowels. Otherwise, the score of this word is 1. The score for the whole list of words is the sum of scores of all words in the list.

Debug the given function score_words such that it returns a correct score.

Your function will be tested on several cases by the locked template code.

HackerRank Words score problem solution in Python 2.

def is_vowel(letter):
    return letter in ['a', 'e', 'i', 'o', 'u', 'y']

def score_words(words):
    score = 0
    for word in words:
        num_vowels = 0
        for letter in word:
            if is_vowel(letter):
                num_vowels += 1
        if num_vowels % 2 == 0:
            score += 2
        else:
            score += 1
    return score

Problem solution in Python 3 programming.

def is_vowel(letter):
    return letter in ['a', 'e', 'i', 'o', 'u', 'y']

def score_words(words):
    score = 0
    for word in words:
        num_vowels = 0
        for letter in word:
            if is_vowel(letter):
                num_vowels += 1
        if num_vowels % 2 == 0:
            score += 2
        else:
            score += 1
            
    return score