HackerRank Finding the percentage solution in python

In this HackerRank Finding the percentage problem solution in python, The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

Problem solution in Python 2 programming.

n=int(raw_input())

dic={}

for i in range(n):
	line=raw_input().split()
	dic[line[0]]=sum(map(float,line[1:]))/3.0

print '%.2f' % dic[raw_input()]

Problem solution in Python 3 programming.

if __name__ == '__main__':
    n = int(input())
    student_marks = {}
    for _ in range(n):
        name, *line = input().split()
        scores = list(map(float, line))
        student_marks[name] = scores
    query_name = input()

    if query_name in student_marks:
        x = ((float(student_marks[query_name][0]) + float(student_marks[query_name][1]) + float(student_marks[query_name][2])) / 3)
    
    print('%.2f' % x)

Problem solution in pypy programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
d={}
for _ in range(int(raw_input())):
    item = raw_input().split()
    name = item[0]
    grade = [float(a) for a in item[1:]]  
    d[name] = grade
request = raw_input().strip()

avg = reduce(lambda x, y: x + y, d[request])/len(d[request])
print '%.2f' %(avg)

Problem solution in pypy3 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT

n = int(input())

c = 1
students = {}
while c <= n :
    line = input()
    inList = line.split()
    students[inList[0]] = inList[1:4]
    c += 1
    
student = input()

sum = 0
for gs in students[student]:
    sum = sum + float(gs)

print('{0:.2f}'.format(sum / 3))