HackerRank Group() Groups() & Groupdict() solution in python

HackerRank Group() Groups() & Groupdict() solution in Python – In this Group(), Groups(), & Groupdict() problem, You are given a string S. Your task is to find the first occurrence of an alphanumeric character in S (read from left to right) that has consecutive repetitions.

_group()

A group() expression returns one or more subgroups of the match.
_Code

>>> import re
>>> m = re.match(r'(\w+)@(\w+)\.(\w+)','username@hackerrank.com')
>>> m.group(0)       # The entire match 
'username@hackerrank.com'
>>> m.group(1)       # The first parenthesized subgroup.
'username'
>>> m.group(2)       # The second parenthesized subgroup.
'hackerrank'
>>> m.group(3)       # The third parenthesized subgroup.
'com'
>>> m.group(1,2,3)   # Multiple arguments give us a tuple.
('username', 'hackerrank', 'com')

_groups()

A groups() expression returns a tuple containing all the subgroups of the match.
_Code

>>> import re
>>> m = re.match(r'(\w+)@(\w+)\.(\w+)','username@hackerrank.com')
>>> m.groups()
('username', 'hackerrank', 'com')

_groupdict()

A groupdict() expression returns a dictionary containing all the named subgroups of the match, keyed by the subgroup name.
_Code

>>> m = re.match(r'(?P<user>\w+)@(?P<website>\w+)\.(?P<extension>\w+)','myname@hackerrank.com')
>>> m.groupdict()
{'website': 'hackerrank', 'user': 'myname', 'extension': 'com'}

HackerRank Group() Groups() & Groupdict() solution in Python 2.

from __future__ import print_function
import re
r=re.search(r'([0-9a-zA-Z])1',raw_input())
print(r.group(1) if r else -1)

Group() Groups() & Groupdict() solution in Python 3.

# Enter your code here. Read input from STDIN. Print output to STDOUT
import re
m = re.findall(r"([A-Za-z0-9])1+",input())
if m:
    print(m[0])
else:
    print(-1)

Problem solution in pypy programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
import re
s=raw_input()
m=re.search(r'([a-z0-9])1+',s)
if m is None:
    print -1
else:
    print m.group(0)[1]

Problem solution in pypy3 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
import re
m = re.search(r'([a-zA-Z0-9])1', input().strip())
print(m.group(1) if m else -1)