HackerRank Validating UID solution in python YASH PAL, 31 July 2024 In this Validating UID problem, ABCXYZ company has up to 100 employees. The company decides to create a unique identification number (UID) for each of its employees. The company has assigned you the task of validating all the randomly generated UIDs. Topics we are covering Toggle Problem solution in Python 2 programming.Problem solution in Python 3 programming.Problem solution in pypy programming.Problem solution in pypy3 programming. Problem solution in Python 2 programming. import re for i in range(int(raw_input())): N = raw_input().strip() if N.isalnum() and len(N) == 10: if bool(re.search(r'(.*[A-Z]){2,}',N)) and bool(re.search(r'(.*[0-9]){3,}',N)): if re.search(r'.*(.).*1+.*',N): print 'Invalid' else: print 'Valid' else: print 'Invalid' else: print 'Invalid' Problem solution in Python 3 programming. # Enter your code here. Read input from STDIN. Print output to STDOUT import re for _ in range(int(input())): u = ''.join(sorted(input())) try: assert re.search(r'[A-Z]{2}', u) assert re.search(r'ddd', u) assert not re.search(r'[^a-zA-Z0-9]', u) assert not re.search(r'(.)1', u) assert len(u) == 10 except: print('Invalid') else: print('Valid') Problem solution in pypy programming. # Enter your code here. Read input from STDIN. Print output to STDOUT ids = [] line_num = int(raw_input()) while line_num: ids.append(raw_input()); line_num -= 1; import re for id in ids: chars_count = {char:id.count(char) for char in id} upper = 0 not_alnum = 0; dig = 0; for ch in id: if ch.isupper(): upper += 1 if not ch.isalnum(): not_alnum = 1; if ch.isdigit(): dig += 1; if len(id) != 10: print 'Invalid' elif len(set(chars_count.values())) != 1: print 'Invalid' elif upper < 2: print 'Invalid' elif dig < 3: print 'Invalid' elif not_alnum: print 'Invalid' else: print 'Valid' Problem solution in pypy3 programming. # Enter your code here. Read input from STDIN. Print output to STDOUT import re def valid_uid(uid): if len(re.findall(r"[A-Z]", uid)) < 2 or len(re.findall(r"[0-9]", uid)) < 3 or not re.match(r"[A-Za-z0-9]{10}$", uid) or len(set(uid)) != len(uid): return False return True n = int(input()) for _ in range(n): uid = input() if valid_uid(uid): print("Valid") else: print("Invalid") coding problems solutions Python Solutions