HackerRank Alphabet Rangoli problem solution in python

In this HackerRank Alphabet Rangoli problem solution, You are given an integer, N. Your task is to print an alphabet rangoli of size N. (Rangoli is a form of Indian folk art based on creation of patterns.) 

The center of the rangoli has the first alphabet letter a, and the boundary has the  alphabet letter (in alphabetical order). 

Problem solution in Python 2 programming.

from copy import deepcopy
N = int(raw_input())
row = 2 * (N - 1) + 1
col = (N - 1) * 4 + 1
arr = ['-'] * col
res = []
for _ in xrange(row): res.append(deepcopy(arr))
mr = row / 2
mc = col / 2
for i in xrange(mr + 1):
    ch = ord('a') + i
    for j in xrange(N - i):
        res[mr - i][mc - 2 * j] = chr(ch + j)
        res[mr - i][mc + 2 * j] = chr(ch + j)
        res[mr + i][mc - 2 * j] = chr(ch + j)
        res[mr + i][mc + 2 * j] = chr(ch + j)
for r in res:
    print ''.join(r)

Problem solution in Python 3 programming.

def print_rangoli(size):
    alpha = "abcdefghijklmnopqrstuvwxyz"
    data = [alpha[i] for i in range(n)]
    items = list(range(n))
    items = items[:-1]+items[::-1]
    for i in items:
        temp = data[-(i+1):]
        row = temp[::-1]+temp[1:]
        print("-".join(row).center(n*4-3, "-"))

Problem solution in pypy programming.

import string
def print_rangoli(size):
    alpha = string.ascii_lowercase
    n = size
    L = []
    for i in range(n):
        s = "-".join(alpha[i:n])
        L.append((s[::-1]+s[1:]).center(4*n-3, "-"))
    print('n'.join(L[:0:-1]+L))

Problem solution in pypy3 programming.

import string
alpha = string.ascii_lowercase

n = int(input())
L = []
for i in range(n):
    s = "-".join(alpha[i:n])
    L.append((s[::-1]+s[1:]).center(4*n-3, "-"))
print('n'.join(L[:0:-1]+L))