In this Validating Postal Codes problem, you are just required to check whether string P is a valid postal code or not.
Problem solution in Python 2 programming.
# Enter your code here. Read input from STDIN. Print output to STDOUT def bad(a): k = a[2:] m = zip(a,k) n = [a == b for (a,b) in m] return sum(n) > 1 a = raw_input() try: b = int(a) print b >= 100000 and b <= 999999 and not bad(a) except: print False
Problem solution in Python 3 programming.
def inn(p): return 100000 <= int(p) <= 999999 def imm(p): l = [] for i in range(len(p) - 2): l.append(p[i] != p[i + 2]) return all(l) def is_valid(p): return (p.isdigit() and inn(p)) and (p != "110000")# and imm(p) def main(): p = input() print(is_valid(p)) main()
Problem solution in pypy programming.
# Enter your code here. Read input from STDIN. Print output to STDOUT import re print bool(re.match(r'^(?!(?:.*(.).1.*){2,})(?!.*(.)(.)23)[1-9]d{5}$', raw_input()))
Problem solution in pypy3 programming.
import re contain_6_digits = lambda x: bool(re.fullmatch(r'd{6}', x)) alternate_digits = lambda x: len(re.findall(r'(d)1{1}', x[::2])) + len(re.findall(r'(d)1{1}', x[1::2])) < 2 tests = [contain_6_digits, alternate_digits] s = input() print(all(map(lambda x: x(s), tests)))