In this HackerRank Print function problem solution in python, The included code stub will read an integer, n, from STDIN.
Without using any string methods, try to print the following:
123…n
Note that “…” represents the consecutive values in between.
Problem solution in Python 2 programming.
from __future__ import print_function N = int(input()) print(*range(1,N+1), sep='')
Problem solution in Python 3 programming.
if __name__ == '__main__': n = int(input()) for i in range(1,n+1): print(i,end='')
Problem solution in pypy programming.
# Enter your code here. Read input from STDIN. Print output to STDOUT from __future__ import print_function n = int(raw_input()) for i in xrange(1,n+1): print(i, end = '')
Problem solution in pypy3 programming.
# Enter your code here. Read input from STDIN. Print output to STDOUT from __future__ import print_function n = int(input()) print("".join(map(str, [x for x in range(1, n+1)])))
Where did you get end?
unable to compile
by using end= you can print any thing in row