HackerRank Java Varargs – Simple Addition solution YASH PAL, 31 July 2024 In this HackerRank Java Varargs – Simple Addition problem in java programming Your task is to create the class Add and the required methods so that the code prints the sum of the numbers passed to the function add. HackerRank Java Varargs – Simple Addition problem solution. import java.io.*; import java.lang.reflect.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; class Add { public void add(int... intArgs) { int sum = 0; String separator = ""; for (int i : intArgs) { sum += i; System.out.print(separator + i); separator = "+"; } System.out.println("=" + sum); } } public class Solution { public static void main(String[] args) { try{ BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); int n1=Integer.parseInt(br.readLine()); int n2=Integer.parseInt(br.readLine()); int n3=Integer.parseInt(br.readLine()); int n4=Integer.parseInt(br.readLine()); int n5=Integer.parseInt(br.readLine()); int n6=Integer.parseInt(br.readLine()); Add ob=new Add(); ob.add(n1,n2); ob.add(n1,n2,n3); ob.add(n1,n2,n3,n4,n5); ob.add(n1,n2,n3,n4,n5,n6); Method[] methods=Add.class.getDeclaredMethods(); Set<String> set=new HashSet<>(); boolean overload=false; for(int i=0;i<methods.length;i++) { if(set.contains(methods[i].getName())) { overload=true; break; } set.add(methods[i].getName()); } if(overload) { throw new Exception("Overloading not allowed"); } } catch(Exception e) { e.printStackTrace(); } } } Second solution import java.io.*; import java.lang.reflect.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; class Add { public void add(Integer... arguments) { Integer numArgs = arguments.length; Integer total = 0; StringBuilder sb = new StringBuilder(); for(int i =0; i < numArgs; i++) { Integer arg = arguments[i]; total += arg; if(i != 0) { sb.append("+"); } sb.append(arg); } sb.append("=").append(total); System.out.println(sb.toString()); } } public class Solution { public static void main(String[] args) { try{ BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); int n1=Integer.parseInt(br.readLine()); int n2=Integer.parseInt(br.readLine()); int n3=Integer.parseInt(br.readLine()); int n4=Integer.parseInt(br.readLine()); int n5=Integer.parseInt(br.readLine()); int n6=Integer.parseInt(br.readLine()); Add ob=new Add(); ob.add(n1,n2); ob.add(n1,n2,n3); ob.add(n1,n2,n3,n4,n5); ob.add(n1,n2,n3,n4,n5,n6); Method[] methods=Add.class.getDeclaredMethods(); Set<String> set=new HashSet<>(); boolean overload=false; for(int i=0;i<methods.length;i++) { if(set.contains(methods[i].getName())) { overload=true; break; } set.add(methods[i].getName()); } if(overload) { throw new Exception("Overloading not allowed"); } } catch(Exception e) { e.printStackTrace(); } } } coding problems hackerrank solutions java