In this HackerRank Java Stdin and Stdout I problem in the java programming language, you must read 3 integers from stdin and then print them to stdout. Each integer must be printed on a new line.
HackerRank Java Stdin and Stdout I problem solution
import java.util.*; public class Solution { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int a = scan.nextInt(); // Complete this line int b = scan.nextInt(); // Complete this line int c = scan.nextInt(); System.out.println(a); // Complete this line System.out.println(b); // Complete this line System.out.println(c); } }
The solution in Java 8 programming.
import java.util.*; public class Solution { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int a=sc.nextInt(); int b=sc.nextInt(); int c=sc.nextInt(); System.out.println(a); System.out.println(b); System.out.println(c); } }
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Tengo una solución que también es compatible, intenté usar BufferReader pero da muchísima lata al tratar de leer el input separado por n
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
while(scanner.hasNext()) {
int a = scanner.nextInt();
System.out.println(a);
}
scanner.close();
}