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Programming101
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HackerRank Java Strings Introduction problem solution

YASH PAL, 31 July 2024

In this HackerRank Java Strings introduction problem in java programming This exercise is to test your understanding of Java Strings. A sample String declaration:

String myString = “Hello World!”

The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.

Given two strings of lowercase English letters, A and B, perform the following operations:

  1. Sum the lengths of A and B.
  2. Determine if A is lexicographically larger than B.
  3. Capitalize the first letter in A and B and print them on a single line, separated by a space.
HackerRank Java Strings Introduction problem solution

HackerRank Java Strings Introduction problem solution.

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        
        Scanner sc=new Scanner(System.in);
String A=sc.next();
String B=sc.next();
System.out.println(A.length()+B.length());
System.out.println(A.compareTo(B)>0?"Yes":"No");
System.out.println(A.substring(0, 1).toUpperCase()+A.substring(1, A.length())+" "+B.substring(0, 1).toUpperCase()+B.substring(1, B.length()));
        
    }
}

Second solution in java programming.

    import java.io.*;
    import java.util.*;
    import java.text.*;
    import java.math.*;
    import java.util.regex.*;

    public class Solution {

        public static void main(String[] args) {
            /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
            Scanner sc=new Scanner(System.in);
            String A=sc.next();
            String B=sc.next();
            System.out.println(A.length()+B.length());
            if(A.compareTo(B)<=0)System.out.println("No");
            else System.out.println("Yes");
            System.out.println(A.substring(0, 1).toUpperCase() + A.substring(1)+" "+B.substring(0, 1).toUpperCase() + B.substring(1));
        }
    }
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