HackerRank Java Stack problem solution

In this HackerRank java Stack problem in java programming language A string containing only parentheses is balanced if the following is true: 1. if it is an empty string 2. if A and B are correct, AB is correct, 3. if A is correct, (A) and {A} and [A] are also correct. Given a string, determine if it is balanced or not.

HackerRank Java Stack problem solution.

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static boolean isBalanced(String s) {
        Stack<Character> stack = new Stack<Character>();
        for (int i=0; i<s.length();++i){
            if (s.charAt(i) == '(') stack.push('(');
            else if (s.charAt(i) == '{') stack.push('{');
            else if (s.charAt(i) == '[') stack.push('[');
            else if (s.charAt(i) == ')') {
                if (stack.isEmpty()) return false;
                if (stack.pop() != '(') return false;
            }
            else if (s.charAt(i) == '}') {
                if (stack.isEmpty()) return false;
                if (stack.pop() != '{') return false;
            }
            else if (s.charAt(i) == ']') {
                if (stack.isEmpty()) return false;
                if (stack.pop() != '[') return false;
            }
        }
        return stack.isEmpty();
    }
    
    public static void main(String[] args) {
        Stack<Character> stack = new Stack<Character>();
        Scanner sc = new Scanner(System.in);
        String line;
        while (sc.hasNextLine()){
            line = sc.nextLine();
            if (isBalanced(line)) System.out.println("true");
            else System.out.println("false");
        }
    }
}

Second solution

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    private final static Map<String, String> BRACKETS = createBracketsMap();
    private final static Set<String> CLOSING = new HashSet<String>(Arrays.asList("]", "}", ")"));
    
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while(in.hasNext()) {
            String data = in.next().trim();
            System.out.println(isBalanced(data));
        }
    }
    
    private static Map<String, String> createBracketsMap() {
        Map<String, String> map = new HashMap<String, String>();
        map.put("{", "}");
        map.put("[", "]");
        map.put("(", ")");
        return map;
    }
    
    public static boolean isBalanced(String data) {
        if (data.equals("")) return true;
        Deque<String> stack = new ArrayDeque<String>();
        for (int i = 0; i < data.length(); i++){
            String c = data.substring(i,i+1);  
            if (CLOSING.contains(c)) {
                if (stack.isEmpty()) return false;
                String op = stack.pop();
                if (!BRACKETS.get(op).equals(c)) return false;
            } else {
                stack.push(c);
            }
        }
        return stack.isEmpty();
    }
}

The solution in java8 programming

import java.util.*;
class Solution{
	
	public static void main(String []argh)
	{
		Scanner sc = new Scanner(System.in);
		
		while (sc.hasNext()) {
			String input=sc.next();
    while(input.length() != (input = input.replaceAll("\(\)|\[\]|\{\}", "")).length());
    System.out.println(input.isEmpty());
		}
		
	}
}

Second solution

import java.io.*;
import java.math.BigInteger;
import java.util.Stack;
import java.util.StringTokenizer;

public class Solution {
    StringTokenizer st;
    BufferedReader in;
    PrintWriter out;

    public static void main(String[] args) throws NumberFormatException, IOException {
        final Solution solver = new Solution();
        long time = System.currentTimeMillis();
        solver.open();
        solver.solve();
        //System.out.println("Spend time:" + (System.currentTimeMillis() - time));
        solver.close();
    }

    public void open() throws IOException {
        in = new BufferedReader(new InputStreamReader(System.in));
        out = new PrintWriter(new OutputStreamWriter(System.out));
        //in = new BufferedReader(new FileReader("input.txt"));
        //out = new PrintWriter(new FileWriter("output.txt"));
    }

    boolean hasMoreTokens() throws IOException {
        while (st == null || !st.hasMoreTokens()) {
            String line = in.readLine();
            if (line == null)
                return false;
            st = new StringTokenizer(line);
        }
        return true;
    }

    public String nextToken() throws IOException {
        while (st == null || !st.hasMoreTokens()) {
            String line = in.readLine();
            if (line == null)
                return null;
            st = new StringTokenizer(line);
        }
        return st.nextToken();
    }

    public int nextInt() throws NumberFormatException, IOException {
        return Integer.parseInt(nextToken());
    }

    public long nextLong() throws NumberFormatException, IOException {
        return Long.parseLong(nextToken());
    }

    public double nextDouble() throws NumberFormatException, IOException {
        return Double.parseDouble(nextToken());
    }

    boolean between(final BigInteger n, long from, long to) {
        return n.compareTo(BigInteger.valueOf(from)) > -1 &&
                n.compareTo(BigInteger.valueOf(to)) < 1;
    }

    boolean check(final String s) {
        final Stack<Character> stack = new Stack<>();

        for (final char c : s.toCharArray()) {
            switch (c) {
                case '(':
                case '{':
                case '[':
                    stack.push(c);
                    break;
                case ')':
                    if (stack.isEmpty() || stack.pop() != '(')
                        return false;
                    break;
                case '}':
                    if (stack.isEmpty() || stack.pop() != '{')
                        return false;
                    break;
                case ']':
                    if (stack.isEmpty() || stack.pop() != '[')
                        return false;
                    break;
            }
        }

        return stack.isEmpty();
    }

    public void solve() throws NumberFormatException, IOException {
        String s;
        while ((s = in.readLine()) != null) {
            out.println(check(s));
        }
    }

    public void close() {
        out.flush();
        out.close();
    }
}