HackerRank Java Int to String problem solution

In this HackerRank Java Int to String problem in java programming language You are given an integer n, you have to convert it into a string. If your code successfully converts n into a string s the code will print “Good job”. Otherwise it will print “wrong answer”.

HackerRank Java Int to String problem solution.

import java.util.*;
import java.security.*;
public class Solution {
 public static void main(String[] args) {

  DoNotTerminate.forbidExit();

  try {
   Scanner in = new Scanner(System.in);
   int n = in .nextInt();
   in.close();
   //String s=???; Complete this line below

   //Write your code here
   String s = Integer.toString(n);

   
   if (n == Integer.parseInt(s)) {
    System.out.println("Good job");
   } else {
    System.out.println("Wrong answer.");
   }
  } catch (DoNotTerminate.ExitTrappedException e) {
   System.out.println("Unsuccessful Termination!!");
  }
 }
}

//The following class will prevent you from terminating the code using exit(0)!
class DoNotTerminate {

 public static class ExitTrappedException extends SecurityException {

  private static final long serialVersionUID = 1;
 }

 public static void forbidExit() {
  final SecurityManager securityManager = new SecurityManager() {
   @Override
   public void checkPermission(Permission permission) {
    if (permission.getName().contains("exitVM")) {
     throw new ExitTrappedException();
    }
   }
  };
  System.setSecurityManager(securityManager);
 }
}

Second solution

import java.util.*;
import java.security.*;
public class Solution {
 public static void main(String[] args) {

  DoNotTerminate.forbidExit();

  try {
   Scanner in = new Scanner(System.in);
   int n = in .nextInt();
   in.close();
   //String s=???; Complete this line below

   //Write your code here
   String s = String.valueOf(n);

   
   if (n == Integer.parseInt(s)) {
    System.out.println("Good job");
   } else {
    System.out.println("Wrong answer.");
   }
  } catch (DoNotTerminate.ExitTrappedException e) {
   System.out.println("Unsuccessful Termination!!");
  }
 }
}

//The following class will prevent you from terminating the code using exit(0)!
class DoNotTerminate {

 public static class ExitTrappedException extends SecurityException {

  private static final long serialVersionUID = 1;
 }

 public static void forbidExit() {
  final SecurityManager securityManager = new SecurityManager() {
   @Override
   public void checkPermission(Permission permission) {
    if (permission.getName().contains("exitVM")) {
     throw new ExitTrappedException();
    }
   }
  };
  System.setSecurityManager(securityManager);
 }
}