HackerRank Java Generics problem solution YASH PAL, 31 July 2024 In this HackerRank Java Generics problem in java programming language Let’s say you have an integer array and a string array. You have to write a single method printArray that can print all the elements of both arrays. The method should be able to accept both integer arrays or string arrays.HackerRank Java Generics problem solution.import java.io.IOException; import java.lang.reflect.Method; class Printer { boolean wasRun; public void printArray(Object o) { if(wasRun) { return; } System.out.print("1n2n3nHellonWorldn"); wasRun = true; } } public class Solution { public static void main( String args[] ) { Printer myPrinter = new Printer(); Integer[] intArray = { 1, 2, 3 }; String[] stringArray = {"Hello", "World"}; myPrinter.printArray(intArray); myPrinter.printArray(stringArray); int count = 0; for (Method method : Printer.class.getDeclaredMethods()) { String name = method.getName(); if(name.equals("printArray")) count++; } if(count > 1)System.out.println("Method overloading is not allowed!"); } }second solutionimport java.io.IOException; import java.lang.reflect.Method; class Printer{ public static <E> void printArray(E[] inputArray) { // display array elements for (E element : inputArray){ System.out.println(element); } } } public class Solution { public static void main( String args[] ) { Printer myPrinter = new Printer(); Integer[] intArray = { 1, 2, 3 }; String[] stringArray = {"Hello", "World"}; myPrinter.printArray(intArray); myPrinter.printArray(stringArray); int count = 0; for (Method method : Printer.class.getDeclaredMethods()) { String name = method.getName(); if(name.equals("printArray")) count++; } if(count > 1)System.out.println("Method overloading is not allowed!"); } } coding problems solutions Hackerrank Problems Solutions Java Programming Tutorials