C program to illustrates the use of continue statement

 
#include<stdio.h>
#include<conio.h>
#include<math.h>

void main()
{
    int count, negative;
    double number, sqroot;

    printf("Enter 9999 to STOPn");
    count=0;
    negative=0;

    while(count<=100)
    {
        printf("Enter a number: ");
        scanf("%f",&number);

        if(number==9999)
            break;

        if(number<0)
        {
            printf("Number is negativen");
            negative++;
            continue;
        }

        sqroot=sqrt(number);
        printf("Number=%1f square root=%1fn",number,sqroot);
        count++;
    }

    printf("Number of items done=%dn",count);
    printf("Negative items=%dn",negative);
    printf("END OF DATA");
}

 
Enter 9999 to STOP
Enter a number: 25.0
Number = 25.000000
Square root = 5.000000
Enter a number: 40.5
Number = 40.500000
Square root = 6.363961
Enter a number: -9
Number is negative
Enter a number: 16
Number = 16.000000
Square root = 4.000000
Enter a number: -14.75
Number is negative
Enter a number: 80
Number = 80.000000
Square root = 8.944272

Enter a number: 9999
Number of items done = 4
Negative items = 2
END OF DATA