HackerRank Weighted Uniform Strings problem solution

In this HackerRank Weighted Uniform Strings, problem Given a string, s, let U be the set of weights for all possible uniform contiguous substrings of string s. There will be n queries to answer where each query consists of a single integer. Create a return array where for each query, the value is Yes if query[i] related to U. Otherwise, append No.

Problem solution in Python programming.

#!/bin/python3

import sys
from collections import Counter

def weight_of_letter(l):
    return ord(l) - 96

def get_uniform_subsets(s):
    cnt = Counter()
    curr = 0
    last = ""
    for ch in s:
        if ch == last:
            curr += 1
        else:
            last = ch
            curr = 1
        if curr > cnt[ch]: cnt[ch] = curr

    weights = set()
    for i in cnt:
        for j in range(cnt[i]):
            weights.add((j+1)*weight_of_letter(i))
    return weights
            
s = input().strip()
weights = get_uniform_subsets(s)
n = int(input().strip())
for a0 in range(n):
    x = int(input().strip())
    # your code goes here
    if x in weights:
        print("Yes")
    else:
        print("No")

Problem solution in Java Programming.

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String s = in.next();
        int n = in.nextInt();
        HashSet<Integer> map = new HashSet<Integer>();
        int i, j, curr;
        i = 0;

        while (i < s.length()) {
            j = i;
            curr = 0;
            while (j < s.length() && s.charAt(j) == s.charAt(i)) {
                curr += s.charAt(j++) - 'a' + 1;
                map.add(curr);
            }
            i = j;
        }
        for(int a0 = 0; a0 < n; a0++){
            int x = in.nextInt();
            // your code goes here
            if (map.contains(x))
                System.out.println("Yes");
            else
                System.out.println("No");
        }
    }
}

Problem solution in C++ programming.

#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <unordered_map>

using namespace std;

int maxlen[26] = {};

int main(){
    string s;
    cin >> s;
    int len = s.size();
    int i = 0;
    while (i < len) {
        int j = i;
        while (j < len && s[i] == s[j]) j++;
        maxlen[s[i] - 'a'] = max(maxlen[s[i] - 'a'], j - i);
        i = j;
    }

    int n;
    cin >> n;
    for(int a0 = 0; a0 < n; a0++){
        int x;
        cin >> x;
        bool poss = false;
        for (i = 0; i < 26; i++) {
            if (x % (i + 1) == 0) {
                int y = x / (i + 1);
                poss |= (y <= maxlen[i]);
            }
        }
        cout << (poss ? "Yes" : "No") << endl;
    }
    return 0;
}

Problem solution in C programming.

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
    char* s = (char *)malloc(512000 * sizeof(char));
    scanf("%s",s);
    int n; 
    scanf("%d",&n);
    int i;
    int *c = (int *)malloc(10000000 * sizeof(int));
    int sum;
    i = -1;
    while (s[++i] != '')
    {
        if (i > 0 && s[i - 1] == s[i])
            sum = (s[i] - 96) + sum;
        else
            sum = s[i] - 96;
        c[sum - 1] = sum;
    }
    free(s);
    for(int a0 = 0; a0 < n; a0++){
        int x; 
        scanf("%d",&x);
        // your code goes here
        if (c[x - 1] == x)
            printf("Yesn");
        else
            printf("Non");
    }
    return 0;
}

Problem solution in JavaScript programming.

process.stdin.resume();
process.stdin.setEncoding('ascii');

var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;

process.stdin.on('data', function (data) {
    input_stdin += data;
});

process.stdin.on('end', function () {
    input_stdin_array = input_stdin.split("n");
    main();    
});

function readLine() {
    return input_stdin_array[input_currentline++];
}

/////////////// ignore above this line ////////////////////

function main() {
    var s = readLine();
    var n = parseInt(readLine());
    let alphabet = "abcdefghijklmnopqrstuvwxyz";
    let weights = {};
    alphabet.split("").forEach((letter, index) => {
       weights[letter] = index+1; 
    });
    let blocks = {};
    let currentSum = 0;
    let currentLetter = s[0];
    for(let i = 0;i<s.length;i++){
        currentSum += weights[currentLetter];
        blocks[currentSum] = true;
        if(i+1 < s.length && s[i+1] !== currentLetter){
            currentSum = 0;
            currentLetter = s[i+1];
        }
    }
    
    for(var a0 = 0; a0 < n; a0++){
        var x = parseInt(readLine());
        // your code goes here
        if(blocks[x] === true){
            console.log("Yes");
        }else{
            console.log("No");
        }
    }

}