HackerRank Pangrams problem solution

In this HackerRank Pangrams, problem Given a sentence determines whether it is a pangram in the English alphabet. Ignore case. Return either pangram or not pangram as appropriate.

Problem solution in Python programming.

s = set(list(input().lower()))
letters = []
for i in range(97, 122):
    letters.append(i)

for i, element in enumerate(s):
    if ord(element) in letters:
        letters.remove(ord(element))

if len(letters) > 0:
    print("not", end=" ")
print("pangram")

Problem solution in Java Programming.

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        try (Scanner sc = new Scanner(System.in)) {
            String line = sc.nextLine();
            String lower = line.toLowerCase();
            lower = lower.replace(" ", "");
            
            Set<Character> chars = new HashSet<Character>();
            for (int i = 0; i < lower.length(); ++i) {
                chars.add(lower.charAt(i));
            }
            if (chars.size() != 26) {
                System.out.print("not ");
            }
            System.out.println("pangram");
        }
    }
}

Problem solution in C++ programming.

#include <iostream>
#include <iomanip>
#include <cstdio>
#include <math.h>
#include <algorithm>
#include <queue>
#include <string>
#include <fstream>
#include <vector>
#include <stack>
#include <map>
#include <set>
#include <ctime>

#define all(x) (x).begin(), (x).end()
#define pb push_back
#define float long double
#define LL long long
#define itn int
#define mp make_pair
#define x first
#define y second

using namespace std;

int main(){

	string s;
	vector<int> a(256, 0);
	getline(cin, s);
	for (int i = 0; i < s.length(); i++){
		a[s[i]]++;
	}
	for (char c = 'a'; c <= 'z'; c++){
		if (a[c] + a[c - 'a' + 'A'] == 0){
			cout << "not pangramn";
			return 0;
		}
	}
	cout << "pangramn";
	
	return 0;
}

Problem solution in C programming.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

char ss[1001];
int mark[26] = {0};

int main(){
	int l, i;
	gets(ss);
	l = strlen(ss);
	for(i=0; i<l; i++){
		if(ss[i]>='a' && ss[i]<='z')mark[ss[i]-'a'] = 1;
		else if(ss[i]>='A' && ss[i]<='Z')mark[tolower(ss[i])-'a'] = 1;

	}


	for(i=0; i<26; i++){
//		printf("%d ", i);
		if(!mark[i])break;
	}
//	printf("n");
	if(i==26)printf("pangramn");
	else printf("not pangramn");
	return 0;
}

Problem solution in JavaScript programming.

function processData(input) {
    //Enter your code here
    var lowerInput = input.toLowerCase();
    var letterArray = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];
    for(var i = 0, l = letterArray.length; i < l; i++) {
        if(lowerInput.toLowerCase().indexOf(letterArray[i]) == -1) {
            console.log('not pangram');
            return false;
        }
    }
    console.log('pangram');
} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   processData(_input);
});