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Programming101
Programming101

Learn everything about programming

Hackerrank Day 5 loops 30 days of code solution

YASH PAL, 31 July 202423 March 2025

In this HackerRank Day 5 loops 30 days of code problem solution we need to develop a program that can read an integer input and then print the multiplication table on the output screen.

Hackerrank day 5 loop problem solution
HackerRank Day 5 Loop solution

Hackerrank Day 5 loops 30 days of code solution

Problem solution in Python 2 programming

#!/bin/python

import sys


N = int(raw_input().strip())
for i in range(10):
    print "{} x {} = {}".format(N, i+1, N * (i + 1))

Problem solution in Python 3 programming

#!/bin/python3

import math
import os
import random
import re
import sys



if __name__ == '__main__':
    n = int(input())
    
    for i in range(1,11):
        s = n * i
        print(n,"x",i,"=",s)

Problem solution in java programming

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        for(int i=1;i<11;i++){
            int ans = n * i;
            System.out.println(n + " x " + i + " = " + ans);
        }
    }
}

Problem solution in c++ programming

#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <unordered_map>

using namespace std;


int main(){
    int N;
    cin >> N;
    for (int i=1;i<=10;i++){
        cout<<N<<" x "<<i<<" = "<<N*i<<endl;
    }
    return 0;
}

Problem solution in c programming

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
    int N,i; 
    scanf("%d",&N);
    if(N>=2 && N<= 20){
        for(i=1;i<=10;i++){
            printf("%d x %d = %d n",N,i,(N*i));
        }
    }
    return 0;
}

Problem solution in Javascript programming

process.stdin.resume();
process.stdin.setEncoding('ascii');

var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;

process.stdin.on('data', function (data) {
    input_stdin += data;
});

process.stdin.on('end', function () {
    input_stdin_array = input_stdin.split("n");
    main();    
});

function readLine() {
    return input_stdin_array[input_currentline++];
}

function printdis(N)
{
    var i, temp;
    for (i = 1; i <= 10; i++)
        {
            temp = N * i;
            console.log(N + " x " + i + " = " + temp);
        }
}

/////////////// ignore above this line ////////////////////

function main() {
    var N = parseInt(readLine());
    printdis(N);

}

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