Hackerrank Day 5 loops 30 days of code solution

In this HackerRank Day 5 loops 30 days of code problem solution we need to develop a program that can read an integer input and then print the multiplication table on the output screen.

Objective
In this challenge, we will use loops to do some math.

Task
Given an integer, n, print its first 10 multiples. Each multiple n x i (where 2 <= i <= 10 ) should be printed on a new line in the form: n x i = result.

Example
n=3

The printout should look like this:
3 x 1 = 3
3 x 2 = 6
3 x 3 = 9
3 x 4 = 12
3 x 5 = 15
3 x 6 = 18
3 x 7 = 21
3 x 8 = 24
3 x 9 = 27
3 x 10 = 30

Input Format
A single integer, n.

Constraints
2 <= n <= 20

Output Format
Print 10 lines of output; each line i (where 1<=i<=10) contains the result of nxi in the form:
n x i = result.

Problem solution in Python 2.

#!/bin/python

import sys


N = int(raw_input().strip())
for i in range(10):
    print "{} x {} = {}".format(N, i+1, N * (i + 1))

Problem solution in Python 3.

#!/bin/python3

import math
import os
import random
import re
import sys



if __name__ == '__main__':
    n = int(input())
    
    for i in range(1,11):
        s = n * i
        print(n,"x",i,"=",s)

Problem solution in java

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        for(int i=1;i<11;i++){
            int ans = n * i;
            System.out.println(n + " x " + i + " = " + ans);
        }
    }
}

Problem solution in C++

#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <unordered_map>

using namespace std;


int main(){
    int N;
    cin >> N;
    for (int i=1;i<=10;i++){
        cout<<N<<" x "<<i<<" = "<<N*i<<endl;
    }
    return 0;
}

Problem solution in c.

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
    int N,i; 
    scanf("%d",&N);
    if(N>=2 && N<= 20){
        for(i=1;i<=10;i++){
            printf("%d x %d = %d n",N,i,(N*i));
        }
    }
    return 0;
}

Problem solution in Javascript.

process.stdin.resume();
process.stdin.setEncoding('ascii');

var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;

process.stdin.on('data', function (data) {
    input_stdin += data;
});

process.stdin.on('end', function () {
    input_stdin_array = input_stdin.split("n");
    main();    
});

function readLine() {
    return input_stdin_array[input_currentline++];
}

function printdis(N)
{
    var i, temp;
    for (i = 1; i <= 10; i++)
        {
            temp = N * i;
            console.log(N + " x " + i + " = " + temp);
        }
}

/////////////// ignore above this line ////////////////////

function main() {
    var N = parseInt(readLine());
    printdis(N);

}

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HackerRank Day 6 Let’s Review 30 days of code problem solution