HackerEarth Fill the boxes problem solution YASH PAL, 31 July 2024 In this HackerEarth Fill the boxes problem solution You are given an array of size N, denoting capacity of N boxes, and an integer K, denoting extended capacity factor. You are also given the weights of M balls. Each ith box can accommodate exactly one ball having weight in the range [capacityi, capacityj + K] (both inclusive). Find the maximum number of boxes that can be filled. HackerEarth Fill the boxes problem solution. #include <bits/stdc++.h>#define sflld(n) scanf("%lld",&n)#define sfulld(n) scanf("%llu",&n)#define sfd(n) scanf("%d",&n)#define sfld(n) scanf("%ld",&n)#define sfs(n) scanf("%s",&n)#define ll long long#define s(t) int t; while(t--)#define ull unsigned long long int#define pflld(n) printf("%lldn",n)#define pfd(n) printf("%dn",n)#define pfld(n) printf("%ldn",n)#define lt 2*idx#define rt 2*idx+1#define f(i,k,n) for(i=k;i<n;i++)#define MAXN 100005using namespace std;int wt[MAXN],cap[MAXN];int main(){ int t,i,j; sfd(t); while(t--) { int n,m,k,x; sfd(n); sfd(m); sfd(k); f(i,0,n) sfd(cap[i]); f(i,0,m) sfd(wt[i]); sort(cap,cap+n); sort(wt,wt+m); i=0; j=0; int ans=0; while(i<n&&j<m) { if(cap[i]<=wt[j]&&wt[j]<=cap[i]+k) { ans++; i++; j++; } else if(wt[j]<cap[i]) j++; else i++; } pfd(ans); } return 0;} coding problems