HackerEarth All Vowels problem solution

In this HackerEarth All Vowels problem solution Vowels are very essential characters to form any meaningful word in the English dictionary. There are 5 vowels in the English language – a, e, i, o u. You are given a random string containing only lowercase letters and you need to find if the string contains ALL the vowels.

HackerEarth All Vowels problem solution.

#include <bits/stdc++.h>

#define rep(i,n) for(i=0;i<n;i++)
#define ll long long
#define elif else if
#define pii pair< int, int>
#define mp make_pair
#define pb push_back
using namespace std;
#define gc getchar_unlocked

int randi(int l,int r)
{
  if(r<l)
    return l;
  return rand()%(r-l+1) +l;
}

int done[5]={0};
int main()
{
    freopen("in.txt","r",stdin);
    freopen("out","w",stdout);
    int i,j,n,mi=99999,ma=0;
    cin>>n;
    string st;
    cin>>st;
    rep(i,n)
    {
       if(st[i]=='a')
        done[0]++;
       if(st[i]=='e')
        done[1]++;
       if(st[i]=='i')
        done[2]++;
       if(st[i]=='o')
        done[3]++;
       if(st[i]=='u')
        done[4]++;
    }
    rep(i,5)
    {
      if(!done[i])
      {
        cout<<"NO";
        return 0;
      }
    }
    cout<<"YES";
    return 0;
}

Second solution

#include<bits/stdc++.h>
using namespace std;
int main(){
    
    int N;
    string S;
    cin>>N>>S;
    assert(N>=1 && N<=10000);
    assert(S.length()==N);
    // a,e,i,o,u
    bool flag1=false,flag2=false,flag3=false,flag4=false,flag5=false;
    for(int i=0;i<N;i++){
    if(S[i]=='a')
    flag1=true;
    else if(S[i]=='e')
    flag2=true;
    else if(S[i]=='i')
    flag3=true;
    else if(S[i]=='o')
    flag4=true;
    else if(S[i]=='u')
    flag5=true;
    
    if(flag1==true && flag2==true &&flag3==true && flag4==true && flag5==true)
    break;
    }
    
   if(flag1==true && flag2==true &&flag3==true && flag4==true && flag5==true)
   cout<<"YES"<<endl;
   else
   cout<<"NO"<<endl;
   
}

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