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Leetcode Wiggle Sort II problem solution

YASH PAL, 31 July 2024

In this Leetcode Wiggle Sort II problem solution You are given an integer array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3]…. You may assume the input array always has a valid answer.

Leetcode Wiggle Sort II problem solution

Problem solution in Python.

class Solution:
    def wiggleSort(self, nums: List[int]) -> None:
        nums.sort()
        for i in range(len(nums)//2):
            nums.insert(len(nums)//2 - i - 1,nums.pop())
        if len(nums) % 2 != 0:
            nums.insert(0,nums.pop())
        nums.reverse()
        if len(nums)>1 and nums[-1] == nums[-2]:
            for i in range(len(nums)):
                if nums[i] < nums[-2] and nums[-1] < nums[i+1]:
                    nums[i],nums[-1] = nums[-1],nums[i]
                    break

Problem solution in Java.

class Solution {
    public void wiggleSort(int[] nums) {
        int[] tempArr=Arrays.copyOf(nums,nums.length);
        Arrays.sort(tempArr);
        int t=tempArr.length-1;
        for(int i=0;i<nums.length;i++){
            if(i%2!=0){
                nums[i]=tempArr[t];
                tempArr[t]=-1;
                --t;
            } 
        }
        t=0;
        int k=0;
        for(int i=nums.length-1;i>=0;i--){
            if(i%2==0){
                nums[i]=tempArr[t];
                t++;
            }
        }
    }
}

Problem solution in C++.

class Solution {
public:
    void wiggleSort(vector<int>& nums) {
        vector<int> sorted(nums);
        sort(sorted.begin(),sorted.end());
        int idx = sorted.size()-1;

        for(int i=1; i<nums.size(); i+=2) nums[i] = sorted[idx--];

        for(int i=0; i<nums.size(); i+=2) nums[i] = sorted[idx--];
        
        return;
    }
};

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