Skip to content
Programming101
Programming101

Learn everything about programming

  • Home
  • CS Subjects
    • IoT – Internet of Things
    • Digital Communication
    • Human Values
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
  • HackerRank Solutions
    • HackerRank Algorithms Solutions
    • HackerRank C problems solutions
    • HackerRank C++ problems solutions
    • HackerRank Java problems solutions
    • HackerRank Python problems solutions
Programming101
Programming101

Learn everything about programming

Leetcode Reorder List problem solution

YASH PAL, 31 July 2024

In this Leetcode Reorder List problem solution, we have given the head of a singly linked list. The list can be represented as:

L0 → L1 → … → Ln – 1 → Ln

Reorder the list to be on the following form:

L0 → Ln → L1 → Ln – 1 → L2 → Ln – 2 → …

You may not modify the values in the list’s nodes. Only nodes themselves may be changed.

Leetcode Reorder List problem solution

Problem solution in Python.

class Solution(object):
    def reorderList(self, head):
        q = []
        while head:
            q.append(head)
            head = head.next
        p = dummy = ListNode(0)

        while len(q)>1:
            h = q.pop(0)
            t = q.pop()
            p.next = h
            h.next = t
            p = t
            p.next = None
        
        if q: 
            p.next = q.pop()
            p = p.next
            p.next = None
            
        return dummy.next

Problem solution in Java.

public void reorderList(ListNode head) {
        
        ListNode slow = head;
        ListNode fast = head;
        
        while (fast != null && fast.next != null) {
            slow = slow.next;
            fast = fast.next.next;
        }
        
        ListNode lastHead = null;
        
        if (slow != null) {
            ListNode next = null;
            ListNode prev = null;
            ListNode current = slow.next;
            
            while (current != null) {
                next = current.next;
                current.next = prev;
                prev = current;
                current = next;
            }
            
            slow.next = null;
            lastHead = prev;
        }
        
        if (lastHead != null) {
            ListNode firstHead = head;
            
            ListNode firstHeadNext = null;
            ListNode lastHeadNext = null;
            
            while (firstHead != null && lastHead != null) {
                firstHeadNext = firstHead.next;
                lastHeadNext = lastHead.next;
                
                firstHead.next = lastHead;
                lastHead.next = firstHeadNext;
                
                firstHead = firstHeadNext;
                lastHead = lastHeadNext;
            }
        }
    }

Problem solution in C++.

class Solution {
public:
    ListNode* reverse(ListNode* head)
    {
        if(head==NULL || head->next==NULL)
            return head;
        ListNode* a = reverse(head->next);
        head->next->next=head;
        head->next=NULL;
        return a;
    }
    
    void reorderList(ListNode* head) 
    {
        if(head==NULL)
            return;
        if(head->next==NULL)
            return;
        ListNode* slow=head;
        ListNode* fast=head->next;
        while(fast!=NULL && fast->next!=NULL)
        {
            fast=fast->next->next;
            slow=slow->next;
        }
        ListNode* rev =reverse(slow->next);
        slow->next=NULL;
        ListNode* temp=head;
        ListNode* t2=NULL;
        while(temp && rev)
        {
            ListNode* t1=temp->next;
            temp->next=rev;
            t2=rev;
            temp=t1;
            rev=rev->next;
            t2->next=t1;
            t2=t2->next;
        }
        if(rev!=NULL)
            t2->next=rev; 
    }
};

Problem solution in C.

struct ListNode* reverseList(struct ListNode *head)
{
    if (head==NULL) return NULL;
    struct ListNode *pLast=head, *pCur=head->next, *pNext=NULL;
    head->next=NULL;

    while (pCur!=NULL)
    {
        pNext = pCur->next;
        pCur->next = pLast;

        pLast = pCur;
        pCur = pNext;
    }
    return pLast;
}
 
void reorderList(struct ListNode* head) 
{
    if (head==NULL) return NULL;
    int i,len;
    struct ListNode *pCur=head;

    for(len=0; pCur; len++, pCur=pCur->next); 

    pCur=head;
    for(i=1; i<(len+1)/2 ; i++, pCur=pCur->next);
    
    struct ListNode *pLeft = head;
    struct ListNode *pRight = pCur->next;
    pCur->next = NULL;
    pRight = reverseList(pRight);

    struct ListNode *pLeftNext, *pRightNext;
    while (pLeft && pRight) {
        pLeftNext = pLeft->next;
        pRightNext = pRight->next;
        
        pLeft->next = pRight;
        pRight->next = pLeftNext;
        
        pLeft = pLeftNext;
        pRight = pRightNext;
    }
    
    return head;
}

coding problems

Post navigation

Previous post
Next post
  • How AI Is Revolutionizing Personalized Learning in Schools
  • GTA 5 is the Game of the Year for 2024 and 2025
  • Hackerrank Day 5 loops 30 days of code solution
  • Hackerrank Day 6 Lets Review 30 days of code solution
  • Hackerrank Day 14 scope 30 days of code solution
©2025 Programming101 | WordPress Theme by SuperbThemes