Leetcode Populating Next Right Pointers in Each Node problem solution YASH PAL, 31 July 202419 January 2026 In this Leetcode Populating Next Right Pointers in Each Node problem solution, we have given a perfect binary tree where all leaves are on the same level, and every parent has two children. The binary tree has the following definition:struct Node { int val; Node *left; Node *right; Node *next;}Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL. Initially, all next pointers are set to NULL.Leetcode Populating Next Right Pointers in Each Node problem solution in Python.if root and root.left: root.left.next = root.right root.right.next = root.next.left if root.next else None self.connect(root.left) self.connect(root.right) return root Populating Next Right Pointers in Each Node problem solution in Java.public void connect(TreeLinkNode root) { dfs(root); } private void dfs(TreeLinkNode root){ if(root == null ||(root.left == null && root.right == null)) return; root.left.next = root.right; dfs(root.left); if(root.next != null) root.right.next = root.next.left; dfs(root.right); } Problem solution in C++.class Solution { public: Node* connect(Node* root) { if(root == NULL){ return root; } Node* leftmost = root; while(leftmost->left!=NULL){ Node* cur = leftmost; Node* prev = NULL; while(cur != NULL){ cur->left->next = cur->right; if(prev != NULL){ prev->right->next = cur->left; } prev = cur; cur = cur->next; } leftmost = leftmost->left; } return root; } }; Problem solution in C.void connect(struct TreeLinkNode *root) { struct TreeLinkNode *p = root, *q; if (!root) return; while (p) { q = p; while (q) { if (!q->left) return; q->left->next = q->right; q->right->next = q->next ? q->next->left : NULL; q = q->next; } p = p->left; } } coding problems solutions Leetcode Problems Solutions Leetcode