Skip to content
Programming101
Programming101

Learn everything about programming

  • Home
  • CS Subjects
    • IoT – Internet of Things
    • Digital Communication
    • Human Values
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
    • 100+ Java Programs
    • 100+ C Programs
  • HackerRank Solutions
    • HackerRank Algorithms Solutions
    • HackerRank C problems solutions
    • HackerRank C++ problems solutions
    • HackerRank Java problems solutions
    • HackerRank Python problems solutions
Programming101
Programming101

Learn everything about programming

Leetcode Poor Pigs problem solution

YASH PAL, 31 July 2024

In this Leetcode Poor Pigs problem solution There are buckets buckets of liquid, where exactly one of the buckets is poisonous. To figure out which one is poisonous, you feed some number of (poor) pigs the liquid to see whether they will die or not. Unfortunately, you only have minutesToTest minutes to determine which bucket is poisonous.

You can feed the pigs according to these steps:

  1. Choose some live pigs to feed.
  2. For each pig, choose which buckets to feed it. The pig will consume all the chosen buckets simultaneously and will take no time.
  3. Wait for minutesToDie minutes. You may not feed any other pigs during this time.
  4. After minutesToDie minutes have passed, any pigs that have been fed the poisonous bucket will die, and all others will survive.
  5. Repeat this process until you run out of time.

Given buckets, minutesToDie, and minutesToTest, return the minimum number of pigs needed to figure out which bucket is poisonous within the allotted time.

Leetcode Poor Pigs problem solution

Problem solution in Python.

def poorPigs(self, buckets, minutesToDie, minutesToTest):
    pigs = 0
    while (minutesToTest / minutesToDie + 1) ** pigs < buckets:
        pigs += 1
    return pigs

Problem solution in Java.

public int poorPigs(int buckets, int minutesToDie, int minutesToTest) {
    return (int)Math.ceil(Math.log(buckets)/Math.log(minutesToTest/minutesToDie+1));
}

Problem solution in C++.

int numIntervals = minutesToTest/minutesToDie+1;
    
    if(buckets==1)
        return 0;
    
    
    int numStatesPossible=numIntervals;
    int pig=1;
    while(pig<32 && numStatesPossible<buckets){
        numStatesPossible = numStatesPossible*numIntervals;
        pig++;
    }
    return pig;
}

coding problems

Post navigation

Previous post
Next post
  • HackerRank Separate the Numbers solution
  • How AI Is Revolutionizing Personalized Learning in Schools
  • GTA 5 is the Game of the Year for 2024 and 2025
  • Hackerrank Day 5 loops 30 days of code solution
  • Hackerrank Day 6 Lets Review 30 days of code solution
How to download udemy paid courses for free

Pages

  • About US
  • Contact US
  • Privacy Policy

Programing Practice

  • C Programs
  • java Programs

HackerRank Solutions

  • C
  • C++
  • Java
  • Python
  • Algorithm

Other

  • Leetcode Solutions
  • Interview Preparation

Programming Tutorials

  • DSA
  • C

CS Subjects

  • Digital Communication
  • Human Values
  • Internet Of Things
©2025 Programming101 | WordPress Theme by SuperbThemes