Leetcode Pascal’s Triangle problem solution

def generate(self, numRows):
        result=[]
        for i in range(numRows):
            if(i ==0):
                row = [1]
                result.append(row)
            else:
                row1 = [1]
                j = 1
                while(j < i):
                    row1.append(row[j-1] + row[j])
                    j+=1
                row1.append(1)
                result.append(row1)
                row = row1
        return result

class Solution {
    public List<List<Integer>> generate(int numRows) {
        List<List<Integer>> res = new ArrayList();
        if (numRows < 1) return res;
        List<Integer> initial = new ArrayList();
        initial.add(1);
        res.add(initial);
        for (int i = 1; i < numRows; i++) {
            List<Integer> cur = new ArrayList();
            List<Integer> prev = res.get(i - 1);
            for (int j = 0; j <= i; j++) {
                int tmp = (j > 0 ? prev.get(j - 1) : 0) + (j < i ? prev.get(j) : 0);
                cur.add(tmp);
            }
            res.add(cur);
        }
        return res;
    }
}

vector<vector<int>> generate(int numRows) {
        vector<vector<int>> result(numRows);
        for(int i=0;i<numRows;i++)
        {
            result[i].resize(i+1);
            for(int j=0;j<=i;j++)
            {
                if(j==0 or j==i)
                    result[i][j]=1;
                else
                    result[i][j]=result[i-1][j-1]+result[i-1][j];
            }
        }
        return result;
    }

int** generate(int numRows, int* returnSize, int** returnColumnSizes){
    *returnSize = numRows;
    *returnColumnSizes = (int *) malloc (sizeof(int) * numRows);
	for (int i = 0; i < numRows; i++) 
		(*returnColumnSizes)[i] = i + 1;
    
    int **pascal = (int**)malloc(numRows*sizeof(int*));
    for (int i=0; i<numRows; i++){
        pascal[i] = (int*)malloc((i+1)*sizeof(int));
        pascal[i][0] = 1;
        pascal[i][i] = 1;
        if (i >1 ){
            for (int j=1; j<i; j++){
                pascal[i][j] = pascal[i-1][j-1] + pascal[i-1][j] ;
            }
        }
    }
    return pascal;
}