Skip to content
Programmingoneonone
Programmingoneonone
  • Engineering Subjects
    • Internet of Things (IoT)
    • Digital Communication
    • Human Values
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
    • 100+ Java Programs
    • 100+ C Programs
    • 100+ C++ Programs
  • Solutions
    • HackerRank
      • Algorithms Solutions
      • C solutions
      • C++ solutions
      • Java solutions
      • Python solutions
    • Leetcode Solutions
    • HackerEarth Solutions
  • Work with US
Programmingoneonone
Programmingoneonone

Leetcode Minimum Path Sum problem solution

YASH PAL, 31 July 202418 January 2026

In this Leetcode Minimum Path Sum problem solution, we have Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right, which minimizes the sum of all numbers along its path.

Leetcode Minimum Path Sum problem solution

Leetcode Minimum Path Sum problem solution in Python.

class Solution:
    def minPathSum(self, a: List[List[int]]) -> int:
        if len(a)==0:
            return 0
        m=len(a)
        n=len(a[0])
        c=[[0 for i in range(n)]for j in range(m)]
        c[0][0] = a[0][0]
        for i in range(1, n):
            c[0][i] = a[0][i]+c[0][i-1]
        for i in range(1, m):
            c[i][0] = a[i][0]+c[i-1][0]
        for i in range(1,m):
            for j in range(1,n):
                c[i][j] = min(c[i-1][j], c[i][j-1]) + a[i][j]
        return c[m-1][n-1]

Minimum Path Sum problem solution in Java.

import java.lang.Math;
class Solution {
    public int minPathSum(int[][] grid) 
    {
        int[][] dpStart = new int[grid.length + 1][grid[0].length + 1];
        return dummySoln(dpStart,grid,grid[0].length-1, grid.length-1);
    }
    public int dummySoln(int[][] dp,int[][] grid, int x, int y)
    {
        if(dp[y][x] != 0){return dp[y][x];}
        if(x == y && x == 0)
        {
            return grid[0][0];
        }
        int totalSum = grid[y][x];
        int totalSumLeft = -1;
        int totalSumUp = -1;
        if(x-1 >= 0)
        {
            totalSumLeft = totalSum + dummySoln(dp, grid, x - 1, y);
        }
        if(y-1 >= 0)
        {
            totalSumUp = totalSum + dummySoln(dp, grid, x, y-1);
        }
        if(totalSumLeft == -1 && totalSumUp != -1)
        {
            return totalSumUp;
        }
        if(totalSumLeft != -1 && totalSumUp == -1)
        {
            return totalSumLeft;
        }
        dp[y][x] = Math.min(totalSumLeft, totalSumUp);
        return Math.min(totalSumLeft, totalSumUp);
    }
}

Problem solution in C++.

class Solution {
public:
    int minPathSum(vector<vector<int>>& grid) {
        if (grid.empty())
            return 0;
        int n = grid.size();
        int m = grid[0].size();
        vector<vector<long long int>> res(n, vector<long long int>(m, 0));
        
        res[0][0] = grid[0][0];
        
        for(size_t i = 1; i < n; i++){
            res[i][0] = res[i-1][0]+ grid[i][0];
        }
        for(size_t i = 1; i < m; i++){
            res[0][i] = res[0][i-1]+ grid[0][i];
        }
        
        for(size_t i = 1; i < n; i++){
            for(size_t j = 1; j < m; j++){
                res[i][j] = min(res[i-1][j] + grid[i][j], res[i][j-1] + grid[i][j]);
            }
        }
        
        return res[n-1][m-1];  
    }
};

Problem solution in C.

int min(int a,int b){
    if(a<b)
        return a;
    return b;
}

int minPathSum(int** grid, int gridSize, int* gridColSize){
    int m=gridSize,n=gridColSize[0];
    if(m==1 && n==1)
        return grid[0][0];
    
    if(m==1){
        int minn=0;
        for(int j=0;j<n;j++)
            minn+=grid[0][j];
         return minn;
    }
    else{
        int arr[m][n];
        arr[0][0]=grid[0][0];      
        for(int j=0;j<n;j++){
            for(int i=0;i<m;i++){
                if(i==0 && j==0)
                    continue;
                else if(i==0){
                    arr[i][j]=grid[i][j]+arr[i][j-1];
                }
                else if(j==0)
                    arr[i][0]=grid[i][0]+arr[i-1][j];
                else if(i>0 && i<m){
                    arr[i][j]=grid[i][j]+min(arr[i][j-1],arr[i-1][j]);
                }
            }
        }        
        return arr[m-1][n-1];
    }   
}

coding problems solutions Leetcode Problems Solutions Leetcode

Post navigation

Previous post
Next post

Leave a Reply

Your email address will not be published. Required fields are marked *

Programmingoneonone

We at Programmingoneonone, also known as Programming101 is a learning hub of programming and other related stuff. We provide free learning tutorials/articles related to programming and other technical stuff to people who are eager to learn about it.

Pages

  • About US
  • Contact US
  • Privacy Policy

Practice

  • Java
  • C++
  • C

Follow US

  • YouTube
  • LinkedIn
  • Facebook
  • Pinterest
  • Instagram
©2026 Programmingoneonone | WordPress Theme by SuperbThemes