Leetcode Maximum Depth of Binary Tree problem solution YASH PAL, 31 July 2024 In this Leetcode Maximum Depth of Binary Tree problem solution we have Given the root of a binary tree, return its maximum depth. A binary tree’s maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Problem solution in Python. class Solution(object): def maxDepth(self, root): """ :type root: TreeNode :rtype: int """ return 1 + max(self.maxDepth(root.left), self.maxDepth(root.right)) if root else 0 Problem solution in Java. public int maxDepth(TreeNode root) { return find(root); } public int find(TreeNode root) { if(root == null) { return 0; } return Math.max(find(root.left),find(root.right))+1; } Problem solution in C++. int maxDepth(TreeNode* root) { return depth(root, 1); } int depth(TreeNode* node, int d) { if(node==NULL) return 0; return max(d,max(depth(node->left,d+1),depth(node->right,d+1))); } Problem solution in C. int maxDepth(struct TreeNode* root){ int Depth = 0; void inorder(struct TreeNode ** root, int depth) { depth++; if (root[0]) { inorder(&root[0]->left, depth); if (depth > Depth) { Depth = depth; } inorder(&root[0]->right, depth); } } if (root) inorder(&root, 0); return Depth; } coding problems