Leetcode Jump Game II problem solution YASH PAL, 31 July 202418 January 2026 In this Leetcode Jump Game II problem solution, we have given an array of non-negative integers nums, and you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps. You can assume that you can always reach the last index.Leetcode Jump Game II problem solution in Python.class Solution(object): def jump(self, nums): res = 0 edge = 0 maxEdge = 0 for i in range(len(nums)): if i > edge: edge = maxEdge res += 1 maxEdge = max(maxEdge,i+nums[i]) return res Jump Game II problem solution in Java.class Solution { public int jump(int[] nums) { int ladder = 0; int stair = 1; int jump = 0; for (int level = 0; level < nums.length; level++) { if (level == nums.length - 1) { return jump; } if (nums[level] + level >= ladder) ladder = nums[level] + level; stair--; if (stair == 0) { jump++; stair = ladder - level; if (stair == 0) return -1; } } return jump; } } Problem solution in C++.class Solution { public: int jump(vector<int>& nums) { int jumps = 0 , limit = 0 , next_limit = 0; for(int i = 0;i < nums.size()-1;i++){ next_limit = max(next_limit,i+nums[i]); if(i == limit){ jumps++; limit = next_limit; } } return jumps; } }; Problem solution in C.int jump(int* n, int ns){ if(ns <= 1) return 0; int r = n[0]; if(r >= ns - 1) return 1; int max = r + n[r]; int maxid = r; for(int i = 1; i <= r; i++) if(n[i] + i > max) max = n[i] + i, maxid = i; return jump(&n[maxid], ns - maxid) + 1; } coding problems solutions Leetcode Problems Solutions Leetcode