Skip to content
Programmingoneonone
Programmingoneonone
  • CS Subjects
    • Internet of Things (IoT)
    • Digital Communication
    • Human Values
    • Cybersecurity
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
    • 100+ Java Programs
    • 100+ C Programs
  • HackerRank Solutions
    • HackerRank Algorithms Solutions
    • HackerRank C problems solutions
    • HackerRank C++ problems solutions
    • HackerRank Java problems solutions
    • HackerRank Python problems solutions
Programmingoneonone
Programmingoneonone

Leetcode Increasing Subsequences problem solution

YASH PAL, 31 July 202422 January 2026

In this Leetcode Increasing Subsequences problem solution, we have given an integer array nums, return all the different possible increasing subsequences of the given array with at least two elements. You may return the answer in any order.

The given array may contain duplicates, and two equal integers should also be considered a special case of increasing sequence.

Leetcode Increasing Subsequences problem solution

Leetcode Increasing Subsequences problem solution in Python.

def findSubsequences(self, nums):
        """
        :type nums: List[int]
        :rtype: List[List[int]]
        """

        length = len(nums)
        ans = set()

        def dfs(index, res):
            res += "," + str(nums[index])
            if len(res.split(",")) > 2:
                ans.add(res)
            for i in range(index + 1, length):
                if nums[i] >= nums[index]:
                    dfs(i, res)

        for i in range(length):
            dfs(i, "")
        return [[int(item) for item in x.split(",")[1:]] for x in list(ans)]

Increasing Subsequences problem solution in Java.

public List<List<Integer>> findSubsequences(int[] nums) {
        Set<List<Integer>> set = new HashSet();
        for(int i = 0; i < nums.length; i++) {
            Set<List<Integer>> ts = new HashSet();
            List<Integer> t = new ArrayList();
            t.add(nums[i]);
            ts.add(t);
            dfs(nums, i + 1, ts);
            set.addAll(ts);
        }
        return set.stream().filter(l -> l.size() > 1).collect(Collectors.toList());
    }
    
    public void dfs(int[] a, int i, Set<List<Integer>> set) {
        if(i >= a.length) {
            return;
        }
        Set<List<Integer>> s = new HashSet();
        for(List<Integer> l : set) {
            if(l.get(l.size() - 1) <= a[i]) {
                List<Integer> t = new ArrayList(l);
                t.add(a[i]);
                s.add(t);
            }
        }
        set.addAll(s);
        dfs(a, i + 1, set);
    }

Problem solution in C++.

class Solution {
public:
    vector<vector<int>> findSubsequences(vector<int>& nums) {
        vector<vector<int>> res;
        vector<int> seq;
        dfs(res, seq, nums, 0);
        return res;
    }
    
    void dfs(vector<vector<int>>& res, vector<int>& seq, vector<int>& nums, int pos) {
        if(seq.size() > 1) res.push_back(seq);
        unordered_set<int> hash;
        for(int i = pos; i < nums.size(); ++i) {
            if((seq.empty() || nums[i] >= seq.back()) && hash.find(nums[i]) == hash.end()) {
                seq.push_back(nums[i]);
                dfs(res, seq, nums, i + 1);
                seq.pop_back();
                hash.insert(nums[i]);
            }
        }
    }
};

coding problems solutions Leetcode Problems Solutions Leetcode

Post navigation

Previous post
Next post

Leave a Reply

Your email address will not be published. Required fields are marked *

CLOSE ADS
CLOSE ADS

Pages

  • About US
  • Contact US
  • Privacy Policy

Follow US

  • YouTube
  • LinkedIn
  • Facebook
  • Pinterest
  • Instagram
©2026 Programmingoneonone | WordPress Theme by SuperbThemes