Leetcode Bitwise AND of Numbers Range problem solution

YASH PAL,

In this Leetcode Bitwise AND of Numbers Range problem solution we have Given two integers left and right that represent the range [left, right], return the bitwise AND of all numbers in this range, inclusive.

Leetcode Bitwise AND of Numbers Range problem solution

Problem solution in Python.

import math
class Solution:
    def rangeBitwiseAnd(self, left: int, right: int) -> int:
        ans = 0
        if left == 0 or right == 0: return 0
        while left and right:
            left_most_sbit = int(math.log2(left))
            right_most_sbit = int(math.log2(right))
            if left_most_sbit==right_most_sbit:
                ans = ans | 1<<left_most_sbit
                left = left - (1<<left_most_sbit)
            else:
                break
            right = right - (1<<right_most_sbit)
        return ans

Problem solution in Java.

public int rangeBitwiseAnd(int m, int n) {
        int result = 0, num, i;
        for (i=31;i>=0;i--) {
            num = 1 << i;
            if ((num & n) > 0) {
                if ((num & m) > 0)
                    result += num;
                else
                    break;
            } 
        }
        return result;
    }
}

Problem solution in C++.

class Solution {
public:
    int rangeBitwiseAnd(int m, int n) {
        int i = 0;
        while(m!=n){
            m=m>>1;
            n=n>>1;
            ++i;        
        }
        return m<<i;
    }
};

Problem solution in C.

int rangeBitwiseAnd(int m, int n){
    int sum=0,val1=m,val2=n;
    long int k=1;
    while(m>0){
        if(m&1 && n&1){
            if(val2-val1<k)
                sum+=k;
        }
        m=m>>1;
        n=n>>1;
        k=k<<1;
    }
    return sum;
}

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