Skip to content
Programming101
Programming101

Learn everything about programming

  • Home
  • CS Subjects
    • IoT – Internet of Things
    • Digital Communication
    • Human Values
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
  • HackerRank Solutions
    • HackerRank Algorithms Solutions
    • HackerRank C problems solutions
    • HackerRank C++ problems solutions
    • HackerRank Java problems solutions
    • HackerRank Python problems solutions
Programming101
Programming101

Learn everything about programming

Leetcode Binary Tree Postorder Traversal problem solution

YASH PAL, 31 July 2024

In this Leetcode Binary Tree Postorder Traversal problem solution we have Given the root of a binary tree, return the postorder traversal of its nodes’ values.

Leetcode Binary Tree Postorder Traversal problem solution

Problem solution in Python.

def postorderTraversal(self, root):
	def traverse(node):
		if node is None: return []
		l = traverse(node.left)
		r = traverse(node.right)
		return l + r + [node.val] 
	return traverse(root)

Problem solution in Java.

class Solution {
    public List<Integer> postorderTraversal(TreeNode root) {
        if (root == null) 
            return new ArrayList<Integer>();
        
        List<Integer> list = new ArrayList<Integer>();
        list.addAll(postorderTraversal(root.left));
        list.addAll(postorderTraversal(root.right));
        list.add(root.val);
        
        return list;
    }
}

Problem solution in C++.

class Solution {
public:

    vector<int> postorderTraversal(TreeNode* root) {
        vector<int> ret; 
        stack<pair<int,TreeNode*>> s; 
        if(root){
            s.push({0,root});
        }
        while(s.size()) {
            auto& x = s.top();
            if(x.first == 0) {
                if(x.second->left){
                    x.first = 1; 
                    s.push({0,x.second->left});
                } else if(x.second->right) {
                    x.first = 2;
                    s.push({0,x.second->right});
                } else {
                    x.first = 2; 
                }
            } else if(x.first == 1) {
                if(x.second->right) {
                    s.push({0,x.second->right});
                }
                x.first = 2; 
            } else {
                ret.push_back(x.second->val);
                s.pop();
            }
        }
        return ret; 
    }
};

Problem solution in C.

int nodeCount(struct TreeNode *root){
    if(!root) return 0;
    return 1 + nodeCount(root->left) + nodeCount(root->right);
}

void postorderTraverse(struct TreeNode *root, int *i, int *postorder){
    if(!root) return;
    postorderTraverse(root->left, i, postorder);
    postorderTraverse(root->right, i, postorder);
    postorder[*i] = root->val;
    (*i)++;
}

int* postorderTraversal(struct TreeNode* root, int* returnSize){
    *returnSize = nodeCount(root);
    int *result = (int *)malloc((*returnSize) * sizeof(int));
    int i = 0;
    postorderTraverse(root, &i, result);
    return result;

}

coding problems

Post navigation

Previous post
Next post
  • How AI Is Revolutionizing Personalized Learning in Schools
  • GTA 5 is the Game of the Year for 2024 and 2025
  • Hackerrank Day 5 loops 30 days of code solution
  • Hackerrank Day 6 Lets Review 30 days of code solution
  • Hackerrank Day 14 scope 30 days of code solution
©2025 Programming101 | WordPress Theme by SuperbThemes