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HackerRank Turn Off the Lights problem solution

YASH PAL, 31 July 2024

In this HackerRank Turn Off the Lights problem solution we have given n, k, and the costs for each button, find and print the minimum cost of turning off all n bulbs if they’re all on initially.

HackerRank Turn Off the Lights problem solution

Problem solution in Python.

#!/bin/python3

import os
import sys

def get_sum(s, c, k, t):
    v = None
    for p in range(s, len(c), 2 * k + 1):
        print(p, end=' ')
        if v:
            t += 2 * k + 1
        else:
            v = 0
            
        v += c[p]
        
    if t < len(c):
        v = None
        
    print(' => ', v, 't=', t)
    return v

#
# Complete the turnOffTheLights function below.
#
def turnOffTheLights(k, c):
    min_sum = None
    for s in range(k + 1):
        summ = get_sum(s, c, k, k + 1 + s)
        if not min_sum or (summ and min_sum > summ):
            min_sum = summ
        
    return min_sum

    
if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')

    n, k = map(int, input().split())
    c = list(map(int, input().rstrip().split()))

    result = turnOffTheLights(k, c)
    fptr.write(str(result) + 'n')
    fptr.close()

{“mode”:”full”,”isActive”:false}

Problem solution in Java.

import java.io.*;
import java.util.*;

public class Solution {

  static long turnOffTheLights(int k, int[] arr) {
    long result = Long.MAX_VALUE;
    for(int beg = 1; beg <= 1 + k; beg++) {
        long cost = 0;
        int nxt = beg;
        while(nxt < arr.length) {
            cost += arr[nxt];
            nxt = nxt + 2 * k + 1;
        }
        nxt = nxt - 2 * k - 1;
        if(nxt + k >= arr.length-1) {
          result = Math.min(cost, result);
        }
    }
    return result;
  }

  public static void main(String[] args) throws IOException {
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    BufferedWriter bw = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

    StringTokenizer st = new StringTokenizer(br.readLine());
    int n = Integer.parseInt(st.nextToken());
    int k = Integer.parseInt(st.nextToken());

    int[] c = new int[n+1];
    st = new StringTokenizer(br.readLine());
    for (int cItr = 1; cItr <= n; cItr++) {
      int cItem = Integer.parseInt(st.nextToken());
      c[cItr] = cItem;
    }

    long result = turnOffTheLights(k, c);

    bw.write(String.valueOf(result));
    bw.newLine();

    bw.close();
    br.close();
  }
}

{“mode”:”full”,”isActive”:false}

Problem solution in C++.

#include <bits/stdc++.h>

using namespace std;

vector<string> split_string(string);


long turnOffTheLights(int k, vector<int> c) {
    
    int n = c.size();
    long long best = 1000000000000000000;
    for (int f = 0; f <= min(k, n-1); ++f)
    {
        //cout << f << endl;
        long long price = 0;
        int i;
        for (i = f; i < n; i+=2*k+1)
        {
            price+=c[i];
            //cout << i << " ";
        }
        
        if (n - i + k  > 0)
        {
            //cout << "skipn";
            continue;
        }
        if (price < best)
            best = price;
    }
    
    return best;
}

int main()
{
    ofstream fout(getenv("OUTPUT_PATH"));

    string nk_temp;
    getline(cin, nk_temp);

    vector<string> nk = split_string(nk_temp);

    int n = stoi(nk[0]);

    int k = stoi(nk[1]);

    string c_temp_temp;
    getline(cin, c_temp_temp);

    vector<string> c_temp = split_string(c_temp_temp);

    vector<int> c(n);

    for (int c_itr = 0; c_itr < n; c_itr++) {
        int c_item = stoi(c_temp[c_itr]);

        c[c_itr] = c_item;
    }

    long result = turnOffTheLights(k, c);

    fout << result << "n";

    fout.close();

    return 0;
}

vector<string> split_string(string input_string) {
    string::iterator new_end = unique(input_string.begin(), input_string.end(), [] (const char &x, const char &y) {
        return x == y and x == ' ';
    });

    input_string.erase(new_end, input_string.end());

    while (input_string[input_string.length() - 1] == ' ') {
        input_string.pop_back();
    }

    vector<string> splits;
    char delimiter = ' ';

    size_t i = 0;
    size_t pos = input_string.find(delimiter);

    while (pos != string::npos) {
        splits.push_back(input_string.substr(i, pos - i));

        i = pos + 1;
        pos = input_string.find(delimiter, i);
    }

    splits.push_back(input_string.substr(i, min(pos, input_string.length()) - i + 1));

    return splits;
}

{“mode”:”full”,”isActive”:false}

Problem solution in C.

#include <assert.h>
#include <limits.h>
#include <math.h>
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char* readline();
char** split_string(char*);

/*
 * Complete the turnOffTheLights function below.
 */
long turnOffTheLights(int k, int c_count, int* c) {
    long totalcost[2*k + 1];
    for(int i = 0; i < 2*k + 1; i++){
        totalcost[i] = 0;
    }
    for(int i = 0; i < c_count; i++){
        totalcost[i%(2*k + 1)] = totalcost[i%(2*k + 1)] + c[i];
    }

    long max = LONG_MAX;
    int low = ((c_count - 1)%(2*k + 1) < k? 0 : (c_count - k - 1)%(2*k + 1));
    int high = ((c_count - 1)%(2*k + 1) > k? k : (c_count - 1)%(2*k + 1));
    

    for(int i = low; i <= high; i++){
        max = (totalcost[i] < max? totalcost[i] : max);
    }
    return max;
}

int main()
{
    FILE* fptr = fopen(getenv("OUTPUT_PATH"), "w");

    char** nk = split_string(readline());

    char* n_endptr;
    char* n_str = nk[0];
    int n = strtol(n_str, &n_endptr, 10);

    if (n_endptr == n_str || *n_endptr != '') { exit(EXIT_FAILURE); }

    char* k_endptr;
    char* k_str = nk[1];
    int k = strtol(k_str, &k_endptr, 10);

    if (k_endptr == k_str || *k_endptr != '') { exit(EXIT_FAILURE); }

    char** c_temp = split_string(readline());

    int c[n];

    for (int c_itr = 0; c_itr < n; c_itr++) {
        char* c_item_endptr;
        char* c_item_str = c_temp[c_itr];
        int c_item = strtol(c_item_str, &c_item_endptr, 10);

        if (c_item_endptr == c_item_str || *c_item_endptr != '') { exit(EXIT_FAILURE); }

        c[c_itr] = c_item;
    }

    long result = turnOffTheLights(k, n, c);

    fprintf(fptr, "%ldn", result);

    fclose(fptr);

    return 0;
}

char* readline() {
    size_t alloc_length = 1024;
    size_t data_length = 0;
    char* data = malloc(alloc_length);

    while (true) {
        char* cursor = data + data_length;
        char* line = fgets(cursor, alloc_length - data_length, stdin);

        if (!line) { break; }

        data_length += strlen(cursor);

        if (data_length < alloc_length - 1 || data[data_length - 1] == 'n') { break; }

        size_t new_length = alloc_length << 1;
        data = realloc(data, new_length);

        if (!data) { break; }

        alloc_length = new_length;
    }

    if (data[data_length - 1] == 'n') {
        data[data_length - 1] = '';
    }

    data = realloc(data, data_length);

    return data;
}

char** split_string(char* str) {
    char** splits = NULL;
    char* token = strtok(str, " ");

    int spaces = 0;

    while (token) {
        splits = realloc(splits, sizeof(char*) * ++spaces);
        if (!splits) {
            return splits;
        }

        splits[spaces - 1] = token;

        token = strtok(NULL, " ");
    }

    return splits;
}

{“mode”:”full”,”isActive”:false}

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