HackerRank Tower Breakers problem solution YASH PAL, 31 July 2024 In this HackerRank Tower Breakers problem solution, Two players are playing a game of Tower Breakers! Player 1 always moves first, and both players always play optimally. The rules of the game are as follows: Initially, there are N towers. Each tower is of height M. The players move in alternating turns. In each turn, a player can choose a tower of height X and reduce its height to Y, where 1 <= Y < X and Y evenly divide X. If the current player is unable to make a move, they lose the game. Given the values of N and M, determine which player will win. If the first player wins, return 1. Otherwise, return 2. Topics we are covering Toggle Problem solution in Python.Problem solution in Java.Problem solution in C++.Problem solution in C. Problem solution in Python. T = int(input()) for t in range(T): n, m = [int(x) for x in input().strip().split()] if m == 1: print(2) else: if n % 2 == 1: print(1) else: print(2) Problem solution in Java. import java.io.*; import java.util.*; public class Solution { public static void main(String[] args) { /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */ Scanner in = new Scanner(System.in); int T = in.nextInt(); int N, M; while (T-- > 0) { N = in.nextInt(); M = in.nextInt(); System.out.println((M != 1 && N%2 == 1)? 1 : 2 ); } } } Problem solution in C++. #include <cmath> #include <cstdio> #include <vector> #include <iostream> #include <algorithm> using namespace std; int main() { int n,x,y; cin>>n; do{ cin>>x>>y; (y==1||x%2==0)?cout<<"2"<<endl:cout<<"1"<<endl; n--; }while(n>0); /* Enter your code here. Read input from STDIN. Print output to STDOUT */ return 0; } Problem solution in C. #include <stdio.h> #include <string.h> #include <math.h> #include <stdlib.h> int main() { int n; scanf("%d", &n); for(int testcase = 0; testcase < n; testcase++) { int num_towers; int height; scanf("%d %d", &num_towers, &height); if(height == 1 || num_towers % 2 == 0) printf("2n"); else printf("1n"); } return 0; } Algorithms coding problems solutions