HackerRank Ruby – Strings – Iteration problem solution

In this HackerRank Ruby – Strings – Iteration problem solution In Ruby 1.8, there’s a single each method (remember Enumerable?) which allowed it to iterate over lines of data. While it might seem like a logical option to have, how would one go about iterating on each byte or each character? It turns out that it was not so clean, and people had to resort to tricks for some of these functionalities.

With Ruby 1.9, each was removed from the String class and is no longer an Enumerable. Instead, we have more explicit choices based on what we need to iterate – bytes, chars, lines or codepoints.

each_byte iterates sequentially through the individual bytes that comprise a string;

each_char iterates the characters and is more efficient than [] operator or character indexing;

each_codepoint iterates over the ordinal values of characters in the string;

each_line iterates the lines.

For example:

> money = “¥1000”

> money.each_byte {|x| p x} # first char represented by two bytes

194

165

49

48

48

48

> money.each_char {|x| p x} # prints each character

“¥”

“1”

“0”

“0”

“0”

Without a doubt, Ruby 1.9 makes iteration easier to understand and implement. Hence, we’ll stick with Ruby 1.9 and later versions for current and other challenges (unless otherwise stated).

Challenge: Write the method count_multibyte_char which takes a string as input and returns the number of multibyte characters (byte size > 1) in it.

For example:

> count_multibyte_char(‘¥1000’)

1

HackerRank Ruby – Strings – Iteration problem solution.

# Your code here
def count_multibyte_char (str)
    character_count = 0
    str.each_char do|char| 
        byte_count = 0
        char.each_byte do |byte|
            byte_count += 1
        end
        if byte_count > 1
            character_count += 1
        end
    end
    return character_count
end

Ruby – Strings – Iteration problem solution.

# Your code here
def count_multibyte_char(s)
    count = 0
    s.each_char do |c|
        count += 1 if c.bytesize > 1
    end
    count
end

Third solution.

# Your code here
def count_multibyte_char(str)
  str.each_codepoint.count{|bytes| bytes > 256}
end