HackerRank Ruby – Enumerable – group_by problem solution YASH PAL, 31 July 2024 In this HackerRank Ruby – Enumerable – group_by problem solution Let’s say you have a list of 100 integers and you want to group them according to their even and odd value.In Ruby, you can easily do this by using group_by method provide by Enumerable module.> (1..5).group_by {|x| x%2}{1=>[1,3,5], 0=>[2, 4]} Of course this is a very simple example and its use can be very complicated in nature.In this challenge, your task is to group the students into two categories corresponding to their marks obtained in a test. The list of students will be provided in a marks hash with student name as key and marks obtained (out of 100) as value pair, along with the pass_marks as an argument. The method group_by_marks must return a Hash containing an array of students who passed as value to Passed key, and those who failed as value to Failed key. If a particular key is empty, don’t return that key.For example,> marks = {“Ramesh”:23, “Vivek”:40, “Harsh”:88, “Mohammad”:60}> group_by_marks(marks, 30)=> {“Failed”=>[[“Ramesh”, 23]], “Passed”=>[[“Vivek”, 40], [“Harsh”, 88], [“Mohammad”, 60]]}Problem solution.def group_by_marks(marks, n) marks.group_by{|key, value| value > n ? "Passed" : "Failed"} end Second solution.def group_by_marks(marks, n) grouped = Hash.new grouped = marks.group_by{ |k,x| x>=n } result=Hash.new if(!grouped[false].nil?) result["Failed"] = grouped[false] end if(!grouped[true].nil?) result["Passed"] = grouped[true] end return result end coding problems solutions Ruby Solutions