HackerRank Plus Minus problem solution

In this HackerRank Plus Minus problem solution, Given an array of integers, calculate the ratios of its elements that are positive, negative, and zero. Print the decimal value of each fraction on a new line with 6 places after the decimal.

Note: This challenge introduces precision problems. The test cases are scaled to six decimal places, though answers with absolute error of up to 10^-4 are acceptable.

Example

arr = [1,1,0,-1,-1]

There are n = 5 elements, two positive, two negative and one zero. Their ratios are 2/5=0.400000, 2/5=0.400000 and 1/5=0.200000. Results are printed as:

0.400000

0.200000

Function Description

Complete the plusMinus function in the editor below.

plusMinus has the following parameter(s):

int arr[n]: an array of integers

Print

Print the ratios of positive, negative and zero values in the array. Each value should be printed on a separate line with 6 digits after the decimal. The function should not return a value.

Input Format

The first line contains an integer, n, the size of the array.

The second line contains n space-separated integers that describe .

Constraints

0 < n <= 100
-100 <= arr[i] <= 100

Output Format

Print the following 3 lines, each to 6 decimals:

proportion of positive values
proportion of negative values
proportion of zeros

HackerRank plus minus solution — hackerrank plus minus solution

HackerRank Plus Minus problem solution in Python.

#!/bin/python3

import math
import os
import random
import re
import sys

# Complete the plusMinus function below.
def plusMinus(arr):
    x,z,y=0,0,0
    for i in range(0,len(arr)):
        if arr[i]>0:
            x = x + 1
        elif arr[i]<0:
            y = y + 1
        else:
            z = z + 1
    print(x/len(arr))
    print(y/len(arr))
    print(z/len(arr))

if __name__ == '__main__':
    n = int(input())

    arr = list(map(int, input().rstrip().split()))

    plusMinus(arr)

Explanation

Problem solution in Java Programming.

import java.text.DecimalFormat;
import java.util.Scanner;


public class Solution {
	public static void main(String args[])
	{
		Scanner scan = new Scanner(System.in);
		int N=Integer.parseInt(scan.nextLine());
		int arr[]= new int[N];
		for(int i=0;i<N;i++)
		{
			arr[i]=scan.nextInt();
		}
		scan.close();
		double pos=0;
		double neg=0;
		double zero=0;
		for(int i=0;i<N;i++)
		{
			if(arr[i]>0)
			{
				pos=pos+1;
			}
			else if(arr[i]<0)
			{
				neg=neg+1;
			}
			else
			{
				zero=zero+1;
			}
		}
		DecimalFormat df= new DecimalFormat("#.000");
		System.out.println(df.format(pos/N));
		System.out.println(df.format(neg/N));
		System.out.println(df.format(zero/N));
	}

}

Problem solution in C++ programming.

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    int N, n, total;
    float pos = 0., neg = 0., zer = 0.;
    
    cin >> N;
    
    total = N;
    
    while (N--) {
        cin >> n;
        if (n > 0) pos++;
        else if (n < 0) neg++;
        else zer++;
    }
    
    cout << pos / total << endl;
    cout << neg / total << endl;
    cout << zer / total << endl;
    
    return 0;
}

Problem solution in C programming.

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    int N,A[100],iTemp;
    float minus = 0,zeros = 0,plus = 0;
    scanf("%d",&N);
    for(iTemp=0;iTemp<N;iTemp++)
    {
        scanf("%d",&A[iTemp]);
        if(A[iTemp] > 0)
        {
            plus++;    
        }
        else if(A[iTemp] == 0)
        {
            zeros++;    
        }
        else
        {
            minus++;    
        }
        
    }
    printf("%.3fn%.3fn%.3fn",plus/N,minus/N, zeros/N);
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */    
    return 0;
}

Problem solution in JavaScript programming.

function processData(input) {
    //Enter your code here
    input = input.split("n");
    var n = input.shift();
    input = input.shift().split(' ');
    var len = input.length;
    
    var neg = 0.0;
    var zero = 0.0;
    var pos = 0.0;
    
    input.forEach(function (num) {
        num = parseInt(num);
        if (num < 0) { neg++ }
        else if (num > 0) { pos++ }
        else { zero++ }
    });

    console.log((pos / len).toPrecision(3));
    console.log((neg / len).toPrecision(3));
    console.log((zero / len).toPrecision(3));
} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   processData(_input);
});

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