HackerRank Conditional Statements solution in C++ Programming

HackerRank C++ Conditional Statements solution – In this HackerRank Conditional Statements problem solution in C++ programming language, if and else are two of the most frequently used conditionals in C/C++, and they enable you to execute zero or one conditional statement among many such dependent conditional statements. We use them in the following ways:

if: This executes the body of bracketed code starting with statement1 if the condition evaluates to true.

if (condition) {

    statement1;

    …

}

if – else: This executes the body of bracketed code starting with statement1 if condition evaluates to true, or it executes the body of code starting with statement2 if condition evaluates to false. Note that only one of the bracketed code sections will ever be executed.

if (condition) {

    statement1;

    …

}

else {

    statement2;

    …

}

if – else if – else: In this structure, dependent statements are chained together and the condition for each statement is only checked if all prior conditions in the chain evaluated to false. Once a condition evaluates to true, the bracketed code associated with that statement is executed and the program then skips to the end of the chain of statements and continues executing. If each condition in the chain evaluates to false, then the body of bracketed code in the else block at the end is executed.

if(first condition) {

    …

}

else if(second condition) {

    …

}

.

.

.

else if((n-1)’th condition) {

    ….

}

else {

    …

}

Given a positive integer n, do the following:

1. If 1 <= n <= 9, print the lowercase English word corresponding to the number (e.g., one for 1, two for 2, etc.)..
2. If n > 9, print Greater than 9.

HackerRank Conditional Statements problem solution in c++ programming.

#include <bits/stdc++.h>

using namespace std;


int main() {
int in;
string num[10] = {"Greater than 9", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};

cin >> in;

if(in > 9){
    cout << num[0];
}
else{
    cout << num[in];
}

return 0;
}

Second solution

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    
    int n;
    cin >> n;
    if(n == 1) {
        cout << "one";
    }
    else if(n == 2) {
        cout << "two";
    }
    else if(n == 3) {
        cout << "three";
    }
    else if(n == 4) {
        cout << "four";
    }
    else if(n == 5) {
        cout << "five";
    }
    else if(n == 6) {
        cout << "six";
    }
    else if(n == 7) {
        cout << "seven";
    }
    else if(n == 8) {
        cout << "eight";
    }
    else if(n == 9) {
        cout << "nine";
    }
    else {
        cout << "Greater than 9";
    }
    
    return 0;
}