In this HackerRank Cats and a Mouse problem, You are given q queries in the form of x, y, and z representing the respective positions for cats A and B, and for mouse C.
Problem solution in Python programming.
#!/bin/python3 import sys q = int(input().strip()) for a0 in range(q): x,y,z = input().strip().split(' ') x,y,z = [int(x),int(y),int(z)] if abs(x-z)>abs(y-z): print('Cat B') elif abs(x-z)<abs(y-z): print('Cat A') else: print('Mouse C')
Problem solution in Java Programming.
import java.io.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; public class Solution { public static void main(String[] args) { Scanner in = new Scanner(System.in); int q = in.nextInt(); for(int a0 = 0; a0 < q; a0++){ int x = in.nextInt(); int y = in.nextInt(); int z = in.nextInt(); int catADist = Math.abs(x-z); int catBDist = Math.abs(y-z); if (catADist == catBDist) { System.out.println("Mouse C"); } else if (catADist < catBDist) { System.out.println("Cat A"); } else { System.out.println("Cat B"); } } } }
Problem solution in C++ programming.
#include <map> #include <set> #include <list> #include <cmath> #include <ctime> #include <deque> #include <queue> #include <stack> #include <string> #include <bitset> #include <cstdio> #include <limits> #include <vector> #include <climits> #include <cstring> #include <cstdlib> #include <fstream> #include <numeric> #include <sstream> #include <iostream> #include <algorithm> #include <unordered_map> using namespace std; int main(){ int q; cin >> q; for(int a0 = 0; a0 < q; a0++){ int x; int y; int z; cin >> x >> y >> z; int d1 = abs(x - z), d2 = abs(y - z); if (d1 < d2) cout << "Cat A" << endl; else if (d1 > d2) cout << "Cat B" << endl; else cout << "Mouse C" << endl; } return 0; }
Problem solution in C programming.
#include <stdio.h> typedef unsigned int u32; typedef int s32; int main() { u32 n;scanf("%u",&n); for (u32 i=0;i<n;i++) { s32 x,y,z;scanf("%d %d %d",&x,&y,&z); s32 dx=x<z?z-x:x-z; s32 dy=y<z?z-y:y-z; if (dx<dy) printf("Cat An"); else if (dx>dy) printf("Cat Bn"); else printf("Mouse Cn"); } }
Problem solution in JavaScript programming.
process.stdin.resume(); process.stdin.setEncoding('ascii'); var input_stdin = ""; var input_stdin_array = ""; var input_currentline = 0; process.stdin.on('data', function (data) { input_stdin += data; }); process.stdin.on('end', function () { input_stdin_array = input_stdin.split("n"); main(); }); function readLine() { return input_stdin_array[input_currentline++]; } /////////////// ignore above this line //////////////////// function main() { var q = parseInt(readLine()); for(var a0 = 0; a0 < q; a0++){ var x_temp = readLine().split(' '); var x = parseInt(x_temp[0]); var y = parseInt(x_temp[1]); var z = parseInt(x_temp[2]); var distA = Math.abs(x - z); var distB = Math.abs(y - z); if( distA === distB){ console.log("Mouse C"); }else if(distA > distB){ console.log("Cat B"); }else{ console.log("Cat A"); } } }