In this Breaking the Records problem you have Given the scores for a season, determine the number of times Maria breaks her records for most and least points scored during the season.
Problem solution in Python programming.
def solution(arr): lo = arr[0] hi = arr[0] lob = 0 hib = 0 for i in range(1,len(arr)): if arr[i] < lo: lob += 1 lo = arr[i] if arr[i] > hi: hib += 1 hi = arr[i] return [hib, lob] if __name__ == "__main__": size = int(input()) arr = [int(t) for t in input().strip().split()] ans = solution(arr) print(str(ans)[1:-1].replace(",",""))
Problem solution in Java Programming.
import java.util.Arrays; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); int[] a = new int[n]; for (int i = 0; i < n; i++) a[i] = in.nextInt(); int min = a[0]; int max = a[0]; int res1 = 0, res2 =0; for (int i = 1; i < n; i++) { if (a[i] > max) { res1++; max = a[i]; } if (a[i] < min) { res2++; min = a[i]; } } System.out.println(res1 + " "+ res2); } }
Problem solution in C++ programming.
#include <cstdio> #include <iostream> #include <ctime> #include <string> #include <vector> #include <cmath> #include <algorithm> #include <cstring> #include <set> #include <cstdlib> #include <ctime> #include <cassert> #include <bitset> #include <fstream> #include <deque> #include <stack> #include <climits> #include <string> #include <queue> #include <memory.h> #include <map> #include <unordered_map> #define ll long long #define ld double #define pii pair <ll, ll> #define mp make_pair using namespace std; int main() { int n; cin >> n; int a = (int)1e9; int b = -1000; int s = 0, r = 0; for (int i = 0; i < n; i++) { int x; scanf("%d", &x); if (x < a) { r++; a = x; } if (x > b) { s++; b = x; } } cout << s - 1 << ' ' << r - 1 << endl; return 0; }
Problem solution in C programming.
#include <math.h> #include <stdio.h> #include <string.h> #include <stdlib.h> #include <assert.h> #include <limits.h> #include <stdbool.h> int main(){ int n; scanf("%d",&n); int min; int countmin = 0; int max; int countmax = 0; int *score = malloc(sizeof(int) * n); for(int score_i = 0; score_i < n; score_i++){ scanf("%d",&score[score_i]); } min = max = score[0]; for (int i = 1; i < n; i++){ if (score[i] > max){ countmax++; max = score[i]; } if (score[i] < min){ countmin++; min = score[i]; } } printf("%d %d", countmax, countmin); return 0; }
Problem solution in JavaScript programming.
process.stdin.resume(); process.stdin.setEncoding('ascii'); var input_stdin = ""; var input_stdin_array = ""; var input_currentline = 0; process.stdin.on('data', function (data) { input_stdin += data; }); process.stdin.on('end', function () { input_stdin_array = input_stdin.split("n"); main(); }); function readLine() { return input_stdin_array[input_currentline++]; } /////////////// ignore above this line //////////////////// function main() { var n = parseInt(readLine()); score = readLine().split(' '); score = score.map(Number); let min = score[0]; let max = score[0]; let min_decreased = 0; let max_increased = 0; // your code goes here for (let i = 1; i < n; i++) { if (score[i] < min) { min = score[i]; min_decreased++ } if (score[i] > max) { max = score[i]; max_increased++; } } console.log(max_increased + ' ' + min_decreased); }
PHP codes
$min = $scores[0];
$max = $scores[0];
$min_score = 0;
$max_score = 0;
for($i=1; $i < count($scores); $i++){
if($scores[$i] < $min){
$min = $scores[$i];
$min_score++;
}
if($scores[$i] > $max){
$max = $scores[$i];
$max_score++;
}
}
echo $max_score.' '.$min_score;
def breakingRecords(scores):
minn = 0
maxx = 0
m = []
x = []
for e in scores:
if m == [] and x == []:
minn += 0
maxx += 0
m.append(e)
x.append(e)
elif e > max(x):
maxx += 1
x.append(e)
m.append(min(m))
elif e < min(m):
minn += 1
m.append(e)
x.append(max(x))
else:
m.append(min(m))
x.append(max(x))
print("*************************")
print("score – "+str(e))
print("minArr – "+str(m))
print("maxArr – "+str(x))
print("CurrentMin – "+str(min(m)))
print("CurrentMax – "+str(max(x)))
print("minCount – "+str(minn)+" maxCount – "+str(maxx))
print("*************************")
return [maxx, minn]