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Programmingoneonone
Programmingoneonone

Learn everything about programming

HackerRank Angry Professor problem solution

YASH PAL, 31 July 202430 November 2025

In this HackerRank Angry Professor problem you have Given the arrival time of each student and a threshold number of attendees, determine if the class is canceled.

hackerrank angry professor problem solution

Problem solution in Python programming.

T = int(input())
for _ in range(T):
    N, K = input().split()
    N = int(N)
    K = int(K)
    students = 0
    arrivals = input().split()
    for i in arrivals:
        if int(i) <= 0:
            students += 1
    if students < K:
        print("YES")
    else:
        print("NO")

Problem solution in Java Programming.

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner scan=new Scanner(System.in);
		int T= scan.nextInt();
		for(int i=0; i<T; i++){
			int numofstudents=0;
			int N=scan.nextInt();
			int K=scan.nextInt();
			for(int j=0;j<N; j++){
				int a= scan.nextInt();
				if( a<=0) numofstudents++;
			}
			if(numofstudents < K) System.out.println("YES");
			else System.out.println("NO");
    }
}
}

Problem solution in C++ programming.

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int a; cin >> a;
    for (int g=0; g<a; g++)
    {
        int b,c; cin >> b >> c;
        int num=0; 
        for (int g=0; g<b; g++)
        {
            int d; cin >> d;
            if (d<=0) num++; 
        }
        if (num>=c)
        {
            cout << "NO" << 'n'; 
        }
        else cout << "YES" << 'n';
    }
    return 0; 
}

Problem solution in C programming.

#include<stdio.h>
#include<stdlib.h>

int main(){
	int i, j , T, N, K, t, counter;
	scanf("%d",&T);
	for(i=0; i<T; i++){
		counter= 0;
		scanf("%d %d",&N,&K);
		//t = malloc(sizeof(int)*N);
		for(j=0; j<N; j++){
			scanf("%d",&t);
			if(t<=0) counter++;
		}
		if(counter < K)printf("YESn");
		else printf("NOn");
	}
	return 0;
}

Problem solution in JavaScript programming.

function processData(input) {
    //Enter your code here
    var res = "No";
    var lines = input.split('n');
    lines.shift(1);
    for(var i = 0; i < lines.length; i += 2) {
      var currentLine = lines[i].split(" ");
      var nextLine = lines[i+1].split(" ");
      var latePeople = 0;
      if(nextLine.length != currentLine[0]){
        process.stdout.write("NOn");
      } else {
          for(var j = 0; j < nextLine.length; j++) {
              if(nextLine[j] > 0) {
                  latePeople++;
              }
          }
          if((currentLine[0] - latePeople) >= currentLine[1]){
                  process.stdout.write("NOn");
          } else {
                  process.stdout.write("YESn");
          }
      }
    } 

} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   processData(_input);
});

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