Skip to content
Programmingoneonone
Programmingoneonone
  • CS Subjects
    • Internet of Things (IoT)
    • Digital Communication
    • Human Values
    • Cybersecurity
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
    • 100+ Java Programs
    • 100+ C Programs
  • HackerRank Solutions
    • HackerRank Algorithms Solutions
    • HackerRank C problems solutions
    • HackerRank C++ problems solutions
    • HackerRank Java problems solutions
    • HackerRank Python problems solutions
  • Work with US
Programmingoneonone
Programmingoneonone

HackerEarth The Psychic Type problem solution

YASH PAL, 31 July 202411 February 2026
In this HackerEarth The Psychic Type problem solution Alakazam has the unique ability to teleport itself during fights. He has realized that he can use this ability not just in Pokemon fights, but also during real-time manipulation of arrays. Abra, his non-evolution form has an interesting array of N integers, A1, A2, …, AN-1, AN.
Since Alakazam wants to try his teleportation power on arrays too, he decides to formalize it: he can move from any position I to a position A[i] in an array of the world. Now, he is currently standing at a position he calls S. He wants you to figure out if he can reach position E.
HackerEarth The Psychic Type problem solution

HackerEarth The Psychic Type problem solution.

#include <iostream>
#include <sstream>
#include <fstream>
#include <string>
#include <iomanip>
#include <vector>
#include <deque>
#include <queue>
#include <stack>
#include <set>
#include <map>
#include <algorithm>
#include <functional>
#include <utility>
#include <bitset>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <cassert>
using namespace std;

#define rep(i,n) for(int i=0;i<n;i++)
#define ll long long int
#define pi pair<ll,ll>
#define pii pair<ll,pi>
#define f first
#define mp make_pair
#define mod 1000000007
#define s second
#define pb push_back
int A[100011];
bool vis[100011];
int main(){

int N;
cin >> N;
for(int i=1;i<=N;i++){
cin >> A[i];
assert(A[i]>=1 and A[i]<=N);
}
int S,E;
cin >> S >> E;
assert(S>=1 and S<=N and E>=1 and E<=N);
while(!vis[S]){
vis[S]=1;
S=A[S];
}
if(vis[E]){
cout<<"Yesn";
}
else{
cout<<"Non";
}
}
coding problems solutions HackerEarth HackerEarth

Post navigation

Previous post
Next post

Leave a Reply

Your email address will not be published. Required fields are marked *

Pages

  • About US
  • Contact US
  • Privacy Policy

Follow US

  • YouTube
  • LinkedIn
  • Facebook
  • Pinterest
  • Instagram
©2026 Programmingoneonone | WordPress Theme by SuperbThemes