Skip to content
Programmingoneonone
Programmingoneonone
  • Engineering Subjects
    • Internet of Things (IoT)
    • Digital Communication
    • Human Values
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
    • 100+ Java Programs
    • 100+ C Programs
    • 100+ C++ Programs
  • Solutions
    • HackerRank
      • Algorithms Solutions
      • C solutions
      • C++ solutions
      • Java solutions
      • Python solutions
    • Leetcode Solutions
    • HackerEarth Solutions
  • Work with US
Programmingoneonone
Programmingoneonone

HackerEarth Studious Amit and His New College problem solution

YASH PAL, 31 July 202416 February 2026
In this HackerEarth Studious Amit and His New College problem solution Amit has been awarded as the most meritorious student award in school. He is proud of it and decides to further improve his performance in his new college. He has to take N courses. The courses are labelled from 1 to N.
 
Some courses might have prerequisites. For example, to take Data Structure course, one needs to take C Programming course first. There are M such pair denoting the course and it’s corresponding prerequisite course which Amit needs to take first in order to successfully finish that particular course.
 
Given the number of courses he needs to take and a list of prerequisites pair, find out whether it is possible for Amit to finish all the courses and once again prove his mettle.
 
 
HackerEarth Studious Amit and His New College problem solution

 

 

HackerEarth Studious Amit and His New College problem solution.

#include<bits/stdc++.h>
using namespace std;
#define N 1000010
int visited[N];
bool f;
vector<int> g[N];
void dfs(int u)
{
visited[u] = 1;
for(auto v : g[u])
{
if(!visited[v])
dfs(v);
else if(visited[v] == 1) //cycle found
f = true;
}
visited[u] = 2;
}
int main()
{
int tc;
scanf("%d",&tc);
while(tc--)
{
f = false;
int n,m;
scanf("%d%d",&n,&m);
for(int i = 1;i <= n;i++)
{
g[i].clear();
visited[i] = 0;
}
for(int i=0;i<m;i++)
{
int u,v;
scanf("%d%d",&u,&v);
g[u].push_back(v);
}
for(int i = 1;i <= n; i++)
{
if(!visited[i])
{
dfs(i);
if(f)
break;
}
}
if(f)
printf("0n");
else
printf("1n");
}
return 0;
}
 
coding problems solutions HackerEarth HackerEarth

Post navigation

Previous post
Next post

Leave a Reply

Your email address will not be published. Required fields are marked *

Programmingoneonone

We at Programmingoneonone, also known as Programming101 is a learning hub of programming and other related stuff. We provide free learning tutorials/articles related to programming and other technical stuff to people who are eager to learn about it.

Pages

  • About US
  • Contact US
  • Privacy Policy

Practice

  • Java
  • C++
  • C

Follow US

  • YouTube
  • LinkedIn
  • Facebook
  • Pinterest
  • Instagram
©2026 Programmingoneonone | WordPress Theme by SuperbThemes