HackerEarth Prom Night problem solution

In this HackerEarth Prom Night problem solution, The Hexagon University of India will be hosting its Prom Night tonight.There would be M boys and N girls at the prom tonight. Each boy wants a girl who is strictly shorter than him. A girl can dance with only one boy and vice-versa. Given the heights of all the boys and girls tell whether it is possible for all boys to get a girl.

HackerEarth Prom Night problem solution.

#include <bits/stdc++.h>
#define _ ios_base::sync_with_stdio(false);cin.tie(0);
using namespace std;
#define pb push_back
#define pob pop_back
#define pf push_front
#define pof pop_front
#define mp make_pair
#define all(a) a.begin(),a.end()
#define bitcnt(x) __builtin_popcountll(x)
#define MOD 1000000007
#define total 5000005
#define M 1000000000001
#define NIL 0
#define MAXN 200001
#define EPS 1e-5
#define INF (1<<28)
typedef unsigned long long int uint64;
typedef long long int int64;
vector<int>b,g;
int main(){
  int t,j,n,m,i;
  freopen("input.txt","r",stdin);
  freopen("output.txt","w",stdout);
  cin>>t;
  while(t--){
b.clear();
g.clear();
  cin>>n>>m;
  for(i=0;i<n;i++){
    cin>>j;
    b.pb(j);
  }
  for(i=0;i<m;i++){
    cin>>j;
    g.pb(j);
  }
  sort(all(b));
  sort(all(g));
  j=0;
  for(i=0;i<m;i++){
    if(j==n)
    break;
    if(g[i]<b[j]){
      j++;
      continue;
    }
  }
  if(j==n)
  printf("YESn");
  else
  printf("NOn");
}
  fclose(stdout);
  return 0;
}

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