HackerEarth Palindromes problem solution

In this HackerEarth Palindromes problem solution Everybody loves palindromes, but Artur doesn’t.

He has a string S that consists of lowercase English letters (‘a’ – ‘z’). Artur wants to find a substring T of S of the maximal length, so that T isn’t a palindrome.

HackerEarth Palindromes problem solution.

#include <bits/stdc++.h>

using namespace std;

int main()
{
  string s;
  cin >> s;
  int n = s.size();
  int cnt = 0;
  for (int i = 0; i < n; i++)
    cnt += s[i] == s[0];
  if (cnt == n)
  {
    cout << "0";
    return 0;
  }
  cnt = 0;
  for (int i = 0; i < n; i++)
    cnt += s[i] == s[n - i -1];
  if (cnt == n)
  {
    cout << n - 1;
    return 0;
  }
  cout << n;
  return 0;
}

Second solution

#include<bits/stdc++.h>

using namespace std;

#define vi vector < int >
#define pii pair < int , int >
#define pb push_back
#define mp make_pair
#define ff first
#define ss second
#define foreach(it,v) for( __typeof((v).begin())it = (v).begin() ; it != (v).end() ; it++ )
#define ll long long
#define llu unsigned long long
#define MOD 1000000007
#define INF 0x3f3f3f3f
#define dbg(x) { cout<< #x << ": " << (x) << endl; }
#define dbg2(x,y) { cout<< #x << ": " << (x) << " , " << #y << ": " << (y) << endl; }
#define all(x) x.begin(),x.end()
#define mset(x,v) memset(x, v, sizeof(x))
#define sz(x) (int)x.size()

bool isPalin(string s)
{
    int l = 0 , r = sz(s) - 1;
    while(l < r && s[l] == s[r])
    {
        l++,r--;
    }
    return (l == r);
}

bool allSame(string s)
{
    int i;
    for(i=1;i<sz(s);i++)
    {
        if(s[i] != s[i-1])
            return 0;
    }
    return 1;
}

int main()
{
    string s;
    cin>>s;
    assert(1 <= sz(s) && sz(s) <= 100000);
    int ans;
    if(allSame(s))
        ans = 0;
    else if(isPalin(s))
        ans = sz(s) - 1;
    else
        ans = sz(s);
    printf("%dn",ans);
    return 0;
}

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