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HackerEarth Maximum borders problem solution

YASH PAL, 31 July 202413 February 2026
In this HackerEarth Maximum borders problem solution, you are given a table with n rows and m columns. Each cell is colored white or black. Considering the shapes created by black cells, what is the maximum border of these shapes?
 
A shape is a set of connected cells. Two cells are connected if they share an edge. Note that no shape has a hole in it.
 
HackerEarth Maximum borders problem solution

 

 
 

HackerEarth Maximum borders problem solution.

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

const int maxn = 1e3 + 14;
char c[maxn][maxn];
int main(){
ios::sync_with_stdio(0), cin.tie(0);
int t;
cin >> t;
while(t--){
int n, m;
cin >> n >> m;
for(int i = 1; i <= n; i++)
cin >> (c[i] + 1);
int ans = 0;
for(int i = 1; i <= n; i++)
for(int j = 1, ptr = 1; j <= m; j = ptr)
if(c[i][j] != '#' || c[i - 1][j] == '#')
ptr++;
else{
while(c[i][ptr] == '#' && c[i - 1][ptr] != '#')
ptr++;
ans = max(ans, ptr - j);
}
for(int i = 1; i <= n; i++)
for(int j = 1, ptr = 1; j <= m; j = ptr)
if(c[i][j] != '#' || c[i + 1][ptr] == '#')
ptr++;
else{
while(c[i][ptr] == '#' && c[i + 1][ptr] != '#')
ptr++;
ans = max(ans, ptr - j);
}
for(int i = 1; i <= m; i++)
for(int j = 1, ptr = 1; j <= n; j = ptr)
if(c[j][i] != '#' || c[j][i - 1] == '#')
ptr++;
else{
while(c[ptr][i] == '#' && c[ptr][i - 1] != '#')
ptr++;
ans = max(ans, ptr - j);
}
for(int i = 1; i <= m; i++)
for(int j = 1, ptr = 1; j <= n; j = ptr)
if(c[j][i] != '#' || c[j][i + 1] == '#')
ptr++;
else{
while(c[ptr][i] == '#' && c[ptr][i + 1] != '#')
ptr++;
ans = max(ans, ptr - j);
}
cout << ans << 'n';
}
}

 

 
coding problems solutions HackerEarth HackerEarth

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