HackerEarth Mathematically beautiful numbers problem solution

In this HackerEarth Mathematically beautiful numbers problem solution While playing a mental math game, you realize that the number k is mathematically beautiful.

You then realize that the number x can be mathematically beautiful if it is represented as a sum of a sequence where each element is a power of k and all the numbers in the sequence are different. Your task is to determine whether the number is mathematically beautiful.

HackerEarth Mathematically beautiful numbers problem solution.

#include<iostream>
using namespace std;
int m[40], t;
int main (){
	cin >> t;
	while(t--){
		for(int i = 0; i < 40; i++)
			m[i] = 0;
		long long int x;
		int k, cnt = 0;
		cin >> x >> k;
		while(x){
			cnt++;
			m[x % k]++;
			x /= k;
		}
		if(m[0] + m[1] == cnt)
			cout << "YESn";
		else
			cout << "NOn";
	}
}

second solution

t = int(input())
while t > 0:
    t -= 1
    x, k = map(int, input().split())
    good = True
    while x > 0:
        good &= x % k < 2
        x //= k
    print("YES" if good else "NO")

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