Skip to content
Programmingoneonone
Programmingoneonone
  • Home
  • CS Subjects
    • Internet of Things (IoT)
    • Digital Communication
    • Human Values
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
    • 100+ Java Programs
    • 100+ C Programs
  • HackerRank Solutions
    • HackerRank Algorithms Solutions
    • HackerRank C problems solutions
    • HackerRank C++ problems solutions
    • HackerRank Java problems solutions
    • HackerRank Python problems solutions
Programmingoneonone

HackerEarth Increasing Subsequence problem solution

YASH PAL, 31 July 2024
In this HackerEarth Increasing Subsequence problem solution Given an array, A, having N integers, an increasing subsequence of this array of length k is a set of k indices i1,i2,…ik, such that 1 <= i1 < i2 < … ik <= N and A[i1] < A[i2] < A[i3] < … < A[ik].
Energy of a subsequence is defined as sum of difference of consecutive numbers in the subsequence. For a given integer k, you need to find out the maximum value of energy among energies of all increasing subsequences of length k.
HackerEarth Increasing Subsequence problem solution

HackerEarth Increasing Subsequence problem solution.

#include<bits/stdc++.h>
#define DEBUG 0
using namespace std;
vector< vector<int> > bit;
int n, k;

int query(int idx, int x){
int ret = INT_MAX;
while(x){
ret = min(bit[idx][x], ret);
x -= (x&(-x));
}
return ret;
}

void update(int idx, int x, int val){
while(x <= n){
bit[idx][x] = min(bit[idx][x], val);
x += (x&(-x));
}
}
vector< vector<int> > ans;
int a[1000010];
int rev[1000010];
int main(){
cin>>n>>k;
for(int i=0; i<=k; i++){
vector<int> v;
for(int j=0; j<=n; j++)v.push_back(0);
bit.push_back(v);
ans.push_back(v);
}
if(DEBUG)cout<<"here"<<endl;
for(int i=0; i<=k; i++){
for(int j=0; j<=n; j++)
bit[i][j] = INT_MAX;
}
if(DEBUG)cout<<"here"<<endl;
map<int, int> m;
for(int i=1; i<=n; i++){
cin>>a[i];
m[a[i]];
}
if(DEBUG)cout<<"here"<<endl;
int cnt = 1;
for(auto it:m){
rev[cnt] = it.first;
m[it.first]=cnt++;
}
int mx = -1;
for(int i=1; i<=n; i++){
int x = m[a[i]];
ans[1][x] = x;
update(1, x, x);
for(int j=2; j<=k; j++){
int res = query(j-1, x-1);
ans[j][x] = res;
update(j, x, res);
}
if(ans[k][x] <= n)
mx = max(mx, a[i]-rev[ans[k][x]]);
}
cout<<mx<<endl;
return 0;
}

Second solution

#include<bits/stdc++.h>
#define INF 1000000007
using namespace std;
vector<vector<int> >bit;
int get(int index,int k)
{
int ans=bit[k][index];
while(index>0)
{
ans=min(ans,bit[k][index]);
index-=index & (-index);
}
return ans;
}
void update(int index,int k,int val,int n)
{
while(index<=n)
{
bit[k][index]=min(bit[k][index],val);
index+= index & (-index);
}
}
int main()
{
int n,k;
cin>>n>>k;
for(int i=0;i<=k;i++)
{
vector<int>temp;
for(int j=0;j<=n;j++)temp.push_back(j);
bit.push_back(temp);
}
for(int i=0;i<=k;i++)for(int j=0;j<=n;j++)bit[i][j]=INF;
map<int,int>mp;
int a[n+5],ans=-1;
for(int i=1;i<=n;i++)
{
cin>>a[i];
ans=max(ans,a[i]);
mp[a[i]]=1;
}
if(k==1){cout<<ans<<"n";return 0;}

ans=-1;
int l=1;
map<int,int> :: iterator it;
for(it=mp.begin();it!=mp.end();it++)
it->second=l++;

for(int i=1;i<=n;i++)
{
int ind=mp[a[i]],val;
update(ind,1,a[i],l);
for(int j=2;j<=k;j++)
{
val=get(ind-1,j-1);
update(ind,j,val,l);
}
//cout<<val<<"n";
ans=max(ans,a[i]-bit[k][ind]);
}
cout<<ans<<"n";
return 0;
}
coding problems solutions

Post navigation

Previous post
Next post

Pages

  • About US
  • Contact US
  • Privacy Policy

Programing Practice

  • C Programs
  • java Programs

HackerRank Solutions

  • C
  • C++
  • Java
  • Python
  • Algorithm

Other

  • Leetcode Solutions
  • Interview Preparation

Programming Tutorials

  • DSA
  • C

CS Subjects

  • Digital Communication
  • Human Values
  • Internet Of Things
  • YouTube
  • LinkedIn
  • Facebook
  • Pinterest
  • Instagram
©2025 Programmingoneonone | WordPress Theme by SuperbThemes