HackerEarth Highest average problem solution YASH PAL, 31 July 2024 In this HackerEarth Highest average problem solution You are given an array A of length N. You have to choose a subset S from given array A, such that the average of S is less than K. You need to print the maximum possible length of S. Topics we are covering Toggle HackerEarth Highest average problem solution.Second solution HackerEarth Highest average problem solution. import java.io.OutputStream;import java.io.IOException;import java.io.InputStream;import java.io.PrintWriter;import java.io.FilterInputStream;import java.io.BufferedInputStream;import java.io.InputStream;public class Main { public static void main(String[] args) { new Thread(null, new Runnable() { public void run() { new Main().solve(); } }, "1", 1 << 26).start(); } void solve() { InputStream inputStream = System.in; OutputStream outputStream = System.out; ScanReader in = new ScanReader(inputStream); PrintWriter out = new PrintWriter(outputStream); Highestaverage solver = new Highestaverage(); solver.solve(1, in, out); out.close(); } static class Highestaverage { public void solve(int testNumber, ScanReader in, PrintWriter out) { int n = in.scanInt(); int ar[] = new int[n]; in.scanInt(ar, n); long[] prefix = new long[n + 1]; for (int i = 1; i <= n; i++) prefix[i] += prefix[i - 1] + ar[i - 1]; CodeHash.Radix_Sort(ar); int q = in.scanInt(); while (q-- > 0) { long k = in.scanInt(); int low = 1; int high = n; int index = 0; while (low <= high) { int mid = (low + high) / 2; if (prefix[mid] < k * mid) { index = mid; low = mid + 1; } else { high = mid - 1; } } out.println(index); } } } static class ScanReader { private byte[] buf = new byte[4 * 1024]; private int index; private BufferedInputStream in; private int total; public ScanReader(InputStream inputStream) { in = new BufferedInputStream(inputStream); } private int scan() { if (index >= total) { index = 0; try { total = in.read(buf); } catch (Exception e) { e.printStackTrace(); } if (total <= 0) return -1; } return buf[index++]; } public int scanInt() { int integer = 0; int n = scan(); while (isWhiteSpace(n)) n = scan(); int neg = 1; if (n == '-') { neg = -1; n = scan(); } while (!isWhiteSpace(n)) { if (n >= '0' && n <= '9') { integer *= 10; integer += n - '0'; n = scan(); } } return neg * integer; } private boolean isWhiteSpace(int n) { if (n == ' ' || n == 'n' || n == 'r' || n == 't' || n == -1) return true; else return false; } public void scanInt(int[] A, int size) { for (int i = 0; i < size; i++) A[i] = scanInt(); } } static class CodeHash { public static void Radix_Sort(int a[]) { int multiplier = 1, len = a.length, max = Integer.MIN_VALUE; int b[] = new int[len]; int bucket[]; for (int i = 0; i < len; i++) if (max < a[i]) max = a[i]; while (max / multiplier > 0) { bucket = new int[10]; for (int i = 0; i < len; i++) bucket[(a[i] / multiplier) % 10]++; for (int i = 1; i < 10; i++) bucket[i] += (bucket[i - 1]); for (int i = len - 1; i >= 0; i--) b[--bucket[(a[i] / multiplier) % 10]] = a[i]; for (int i = 0; i < len; i++) a[i] = b[i]; multiplier *= 10; } } }} Second solution #include<bits/stdc++.h>#define ll long longusing namespace std;int main(){ ios_base::sync_with_stdio(false); cin.tie(NULL); int n; cin>>n; assert(n>=1 && n<=500000); int arr[n+1]; arr[0]=0; for(int i=1;i<=n;i++) { cin>>arr[i]; assert(n>=1 && n<=1000000000); } sort(arr+1,arr+n+1); long prefix[n+1]; prefix[0]=0; for(int i=1;i<=n;i++){ prefix[i]=prefix[i-1]+arr[i]; } vector<double> ar; for(int i=1;i<=n;i++) ar.push_back(prefix[i]/double(i)); int q; cin>>q; assert(q>=1 && q<=500000); while(q--){ long k; cin>>k; assert(k>=1 && k<=1000000000); int idx=lower_bound(ar.begin(),ar.end(),k)-ar.begin(); cout<<idx<<"n"; } return 0;} coding problems solutions