Skip to content
Programmingoneonone
Programmingoneonone
  • Engineering Subjects
    • Internet of Things (IoT)
    • Digital Communication
    • Human Values
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
    • 100+ Java Programs
    • 100+ C Programs
    • 100+ C++ Programs
  • Solutions
    • HackerRank
      • Algorithms Solutions
      • C solutions
      • C++ solutions
      • Java solutions
      • Python solutions
    • Leetcode Solutions
    • HackerEarth Solutions
  • Work with US
Programmingoneonone
Programmingoneonone

HackerEarth Benny and String problem solution

YASH PAL, 31 July 202414 February 2026
In this HackerEarth Benny and String problem solution, Benny loves strings! She also loves to play with strings and make different queries on them.
 
In this problem, Benny has a string s of length n consisting of lowercase Latin letters.
 
Let’s define the next letter for every lowercase Latin letter. For letters from ‘a’ to ‘y’ next letter is next to one in the Latin alphabet, and for ‘z’ the next one is ‘a’.
 
Let’s call the rotation of letter is when we replace it with the next one.
 
You have to answer the following queries about the string s:
  1. ? l r c — where c is lowercase Latin letter, (1 <= l <= r <= n). You have to output the length of the largest sequence consisting of consecutive letters c in s[l,r], where s[l,r] — is the substring of string s starting with sl and ending with sr.
  2. + l r x — you have to rotate every letter in s[l,r] exactly x times, (1 <= l <= r <= n), (0 <= x <= 10^9).
  3. * i c — set si equal to c, where c is some Latin lowercase letter, (1 <= i <= n).
  4. – i x — set si equal to its value before processing the x-th query, (1 <= i <= n), (1 <= x <= j), where j is the index of current query. All queries are indexed starting with 1.
 
 
HackerEarth Benny and String problem solution

 

 

HackerEarth Benny and String problem solution.

#include <iostream>
#include <stdio.h>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <vector>
#include <iomanip>
#include <set>
#include <map>

using namespace std;

#define pb push_back
#define mp make_pair
#define F first
#define S second

const int N = 200500;

int n, q;
char c[N];
char s[N];
char type[N];
int l[N], r[N], x[N], id[N];
vector<int> ids[N];
map<int, char> have[N];

struct TreeNode {
int answer[26];
int sz;
int pref_char, suff_char;
int pref_len, suff_len;
int to_push;
TreeNode () {
for (int i = 0; i < 26; i++) {
answer[i] = 0;
}
sz = pref_char = suff_char = pref_len = suff_len = to_push = 0;
}
} tree[4 * N];

TreeNode combine(TreeNode a, TreeNode b) {
if (a.sz == 0) {
return b;
}
if (b.sz == 0) {
return a;
}
TreeNode c;
c.to_push = 0;
c.sz = a.sz + b.sz;
for (int i = 0; i < 26; i++) {
c.answer[i] = max(a.answer[i], b.answer[i]);
}
c.pref_char = a.pref_char;
c.suff_char = b.suff_char;
c.pref_len = a.pref_len;
c.suff_len = b.suff_len;
if (a.suff_char == b.pref_char) {
c.answer[a.suff_char] = max(c.answer[a.suff_char], a.suff_len + b.pref_len);
}
if (a.pref_len == a.sz && a.pref_char == b.pref_char) {
c.pref_len += b.pref_len;
c.answer[a.pref_char] = max(c.answer[a.pref_char], a.pref_len + b.pref_len);
}
if (b.suff_len == b.sz && a.suff_char == b.pref_char) {
c.suff_len += a.suff_len;
c.answer[b.suff_char] = max(c.answer[b.suff_char], a.suff_len + b.suff_len);
}
return c;
}

void add(int &x, int y) {
x += y;
x %= 26;
}

int tmp_array[26];

void make_push(int ver, int l, int r) {
if (tree[ver].to_push == 0) {
return;
}
add(tree[ver + ver].to_push, tree[ver].to_push);
add(tree[ver + ver + 1].to_push, tree[ver].to_push);
add(tree[ver + ver].pref_char, tree[ver].to_push);
add(tree[ver + ver].suff_char, tree[ver].to_push);
add(tree[ver + ver + 1].pref_char, tree[ver].to_push);
add(tree[ver + ver + 1].suff_char, tree[ver].to_push);
for (int i = 0; i < 26; i++) {
tmp_array[(i + tree[ver].to_push) % 26] = tree[ver + ver].answer[i];
}
for (int i = 0; i < 26; i++) {
tree[ver + ver].answer[i] = tmp_array[i];
}
for (int i = 0; i < 26; i++) {
tmp_array[(i + tree[ver].to_push) % 26] = tree[ver + ver + 1].answer[i];
}
for (int i = 0; i < 26; i++) {
tree[ver + ver + 1].answer[i] = tmp_array[i];
}
tree[ver].to_push = 0;
}

void build(int ver, int l, int r) {
if (l == r) {
tree[ver].answer[s[l] - 'a'] = 1;
tree[ver].pref_char = tree[ver].suff_char = s[l] - 'a';
tree[ver].pref_len = tree[ver].suff_len = 1;
tree[ver].to_push = 0;
tree[ver].sz = 1;
return;
}
int mid = (l + r) >> 1;
build(ver + ver, l, mid);
build(ver + ver + 1, mid + 1, r);
tree[ver] = combine(tree[ver + ver], tree[ver + ver + 1]);
}

void update(int ver, int l, int r, int pl, int pr, int add) {
if (pl > pr) {
return;
}
if (l == pl && r == pr) {
(tree[ver].to_push += add) %= 26;
for (int i = 0; i < 26; i++) {
tmp_array[(i + add) % 26] = tree[ver].answer[i];
}
for (int i = 0; i < 26; i++) {
tree[ver].answer[i] = tmp_array[i];
}
(tree[ver].pref_char += add) %= 26;
(tree[ver].suff_char += add) %= 26;
return;
}
int mid = (l + r) >> 1;
make_push(ver, l, r);
update(ver + ver, l, mid, pl, min(pr, mid), add);
update(ver + ver + 1, mid + 1, r, max(pl, mid + 1), pr, add);
tree[ver] = combine(tree[ver + ver], tree[ver + ver + 1]);
}

char getCharacter(int ver, int l, int r, int pos) {
if (l == r) {
return (char)('a' + tree[ver].pref_char);
}
int mid = (l + r) >> 1;
make_push(ver, l, r);
char result = '
 

Second solution

#include <cstdio>
#include <vector>
#include <cassert>
using namespace std;

int const T = 1 << 17;
int const ALPHA = 26;
int const N = 123456;

int nextchar() {
int c = getchar();
while (c <= 32) c = getchar();
return c;
}

struct node {
int longest[ALPHA];
int first, firstCount;
int last, lastCount;
int len;

node() : first(0), firstCount(0), last(0), lastCount(0), len(0) {
fill(longest, longest + ALPHA, 0);
}
};

node createLetter(int c) {
node ret;
ret.longest[c] = 1;
ret.first = ret.last = c;
ret.len = ret.firstCount = ret.lastCount = 1;
return ret;
}

node operator+(node const &a, node const &b) {
if (a.len == 0) return b;
if (b.len == 0) return a;
node ret;
for (int i = 0; i < ALPHA; i++) {
ret.longest[i] = std::max(a.longest[i], b.longest[i]);
}
ret.len = a.len + b.len;
ret.first = a.first;
ret.firstCount = a.firstCount + (a.firstCount == a.len && b.first == a.first ? b.firstCount : 0);
ret.last = b.last;
ret.lastCount = b.lastCount + (b.lastCount == b.len && b.last == a.last ? a.lastCount : 0);
if (a.last == b.first) {
ret.longest[a.last] = std::max(ret.longest[a.last], a.lastCount + b.firstCount);
}
return ret;
}

node tr[2 * T + 5];
int add[2 * T + 5];
int qa[N], qb[N], qc[N], type[N];
vector<int> acc[N];

node processAdd(node const &v, int add) {
node ret;
for (int i = 0; i < ALPHA; i++) {
ret.longest[(i + add) % ALPHA] = v.longest[i];
}
ret.first = (v.first + add) % ALPHA;
ret.last = (v.last + add) % ALPHA;
ret.len = v.len;
ret.firstCount = v.firstCount;
ret.lastCount = v.lastCount;
return ret;
}

void relax(int v) {
if (add[v] == 0) return;
add[2 * v] += add[v];
add[2 * v + 1] += add[v];
tr[v] = processAdd(tr[v], add[v]);
add[v] = 0;
}

node collect(int v, int l, int r, int left, int right) {
if (r <= left || right <= l) return node();
if (left <= l && r <= right) {
return processAdd(tr[v], add[v]);
}
relax(v);
int mid = (l + r) >> 1;
return collect(v * 2, l, mid, left, right) + collect(v * 2 + 1, mid, r, left, right);
}

void makeAdd(int v, int l, int r, int left, int right, int delta) {
if (r <= left || right <= l) return;
if (left <= l && r <= right) {
add[v] += delta;
return;
}
relax(v);
int mid = (l + r) >> 1;
makeAdd(v * 2, l, mid, left, right, delta);
makeAdd(v * 2 + 1, mid, r, left, right, delta);
tr[v] = processAdd(tr[v * 2], add[v * 2]) + processAdd(tr[v * 2 + 1], add[v * 2 + 1]);
}

void setIt(int v, int l, int r, int x, int y) {
if (l + 1 == r) {
tr[v] = createLetter(y);
add[v] = 0;
return;
}
relax(v);
int mid = (l + r) >> 1;
if (x < mid) setIt(v * 2, l, mid, x, y); else setIt(v * 2 + 1, mid, r, x, y);
tr[v] = processAdd(tr[v * 2], add[v * 2]) + processAdd(tr[v * 2 + 1], add[v * 2 + 1]);
}

int main() {
int n, q;
assert(scanf("%d%d", &n, &q) == 2);
for (int i = 0; i < n; i++) {
setIt(1, 0, T, i, nextchar() - 'a');
}
for (int i = 0; i < q; i++) {
int c = getchar();
while (c <= 32) c = getchar();
type[i] = c;
if (c == '?') {
assert(scanf("%d%d", qa + i, qb + i) == 2);
--qa[i];
qc[i] = nextchar() - 'a';
} else if (c == '+') {
assert(scanf("%d%d%d", qa + i, qb + i, qc + i) == 3);
--qa[i];
qc[i] %= ALPHA;
} else if (c == '*') {
assert(scanf("%d", qa + i) == 1);
--qa[i];
qc[i] = nextchar() - 'a';
} else {
assert(scanf("%d%d", qa + i, qc + i) == 2);
--qa[i];
acc[qc[i] - 1].push_back(i);
}
}
for (int i = 0; i < q; i++) {
for (int x : acc[i]) {
qc[x] = collect(1, 0, T, qa[x], qa[x] + 1).first;
}
if (type[i] == '?') {
printf("%dn", collect(1, 0, T, qa[i], qb[i]).longest[qc[i]]);
} else if (type[i] == '+') {
makeAdd(1, 0, T, qa[i], qb[i], qc[i]);
} else {
setIt(1, 0, T, qa[i], qc[i]);
}
}
}
 
 

;
if (pos <= mid) {
result = getCharacter(ver + ver, l, mid, pos);
} else {
result = getCharacter(ver + ver + 1, mid + 1, r, pos);
}
tree[ver] = combine(tree[ver + ver], tree[ver + ver + 1]);
return result;
}

void setValue(int ver, int l, int r, int pos, char value) {
if (l == r) {
tree[ver] = TreeNode();
tree[ver].sz = 1;
tree[ver].answer[value – ‘a’] = 1;
tree[ver].pref_char = tree[ver].suff_char = value – ‘a’;
tree[ver].pref_len = tree[ver].suff_len = 1;
tree[ver].to_push = 0;
return;
}
int mid = (l + r) >> 1;
make_push(ver, l, r);
if (pos <= mid) {
setValue(ver + ver, l, mid, pos, value);
} else {
setValue(ver + ver + 1, mid + 1, r, pos, value);
}
tree[ver] = combine(tree[ver + ver], tree[ver + ver + 1]);
}

TreeNode get(int ver, int l, int r, int pl, int pr) {
if (pl > pr) {
return TreeNode();
}
make_push(ver, l, r);
if (l == pl && r == pr) {
return tree[ver];
}
int mid = (l + r) >> 1;
TreeNode result = get(ver + ver, l, mid, pl, min(pr, mid));
result = combine(result, get(ver + ver + 1, mid + 1, r, max(pl, mid + 1), pr));
tree[ver] = combine(tree[ver + ver], tree[ver + ver + 1]);
return result;
}

int main() {
scanf(“%d%dn”, &n, &q);
gets(s + 1);
for (int i = 1; i <= q; i++) {
scanf(“%c”, &type[i]);
if (type[i] == ‘?’) {
scanf(“%d%d %c”, &l[i], &r[i], &c[i]);
} else if (type[i] == ‘+’) {
scanf(“%d%d%d”, &l[i], &r[i], &x[i]);
} else if (type[i] == ‘*’) {
scanf(“%d %c”, &id[i], &c[i]);
} else if (type[i] == ‘-‘) {
scanf(“%d%d”, &id[i], &x[i]);
ids[x[i]].pb(id[i]);
}
if (i < q) {
scanf(“n”);
}
}
build(1, 1, n);
TreeNode for_queries;
for (int i = 1; i <= q; i++) {
for (int j = 0; j < (int)ids[i].size(); j++) {
int index = ids[i][j];
have[index][i] = getCharacter(1, 1, n, index);
}
if (type[i] == ‘?’) {
for_queries = get(1, 1, n, l[i], r[i]);
printf(“%dn”, for_queries.answer[c[i] – ‘a’]);
} else if (type[i] == ‘+’) {
update(1, 1, n, l[i], r[i], x[i]);
} else if (type[i] == ‘*’) {
setValue(1, 1, n, id[i], c[i]);
} else if (type[i] == ‘-‘) {
setValue(1, 1, n, id[i], have[id[i]][x[i]]);
}
}
return 0;
}

 

Second solution

 
 
 
coding problems solutions HackerEarth HackerEarth

Post navigation

Previous post
Next post

Leave a Reply

Your email address will not be published. Required fields are marked *

Programmingoneonone

We at Programmingoneonone, also known as Programming101 is a learning hub of programming and other related stuff. We provide free learning tutorials/articles related to programming and other technical stuff to people who are eager to learn about it.

Pages

  • About US
  • Contact US
  • Privacy Policy

Practice

  • Java
  • C++
  • C

Follow US

  • YouTube
  • LinkedIn
  • Facebook
  • Pinterest
  • Instagram
©2026 Programmingoneonone | WordPress Theme by SuperbThemes